如果我们抛出了ServletException,如何在日志中写入任何内容?
如果servlet抛出ServletException,我想在日志中创建一个条目如果我们抛出了ServletException,如何在日志中写入任何内容?,exception,servlets,log4j,Exception,Servlets,Log4j,如果servlet抛出ServletException,我想在日志中创建一个条目 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException{ try { } catch (ServletException e) { log.warn("error"); throw new Serlet
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException{
try {
} catch (ServletException e) {
log.warn("error");
throw new SerletException(e);
}
它会重现吗?这是处理异常的正确方法吗?不,不会有递归,但不需要将异常包装到另一个异常中。只需抛出
e
plain即可
try {
} catch (ServletException e) {
log.warn("error");
throw e;
}
顺便说一句,更好的地方是过滤器
,它映射在/*
的URL模式上,因此您不需要在所有servlet中重复它
try {
chain.doFilter(request, response);
} catch (ServletException e) {
log.warn("error");
throw e;
}