Firebase 颤振：如何实现回调

如何实现回调并返回错误消息？

AuthService类的登录函数：

static void login(String email, String password) async {
    try {
      await FirebaseAuth.instance.signInWithEmailAndPassword(email: email, password: password);
    } catch (e) {
      print(e);
    }
  }

从登录类提交函数：

_submit() {
   // If fail to login then return the error message
   AuthService.login(_email, _password);
}

请尝试以下操作：

Future<AuthResult> login(String email, String password) async {
    try {
    Future<AuthResult> result = await FirebaseAuth.instance.signInWithEmailAndPassword(email: email, password: password);
    return result;
    } catch (e) {
      print(e);
    }
  }

方法

使用Email和Password登录

返回

未来

_submit() {
   // If fail to login then return the error message
   login(_email, _password).then((result) => {
      print(result);
  });
}

  // wrapping the firebase calls
  Future<FirebaseUser> loginUser({String email, String password}) {
    return FirebaseAuth.instance
        .signInWithEmailAndPassword(email: email, password: password);
  }

 userInfo = await AuthService().loginUser(email: _email, password: _password);