Flutter 在Dart中,以Classname为前缀的类常量语法是什么意思?

Flutter 在Dart中,以Classname为前缀的类常量语法是什么意思?,flutter,dart,Flutter,Dart,虽然我认为自己熟悉编程语言Dart,但我还是在for Bloc中偶然发现了以下语法: class AuthenticationState extends Equatable { const AuthenticationState._({ this.status = AuthenticationStatus.unknown, this.user = User.empty, }); const AuthenticationState.unknown() : this._

虽然我认为自己熟悉编程语言Dart,但我还是在for Bloc中偶然发现了以下语法:

class AuthenticationState extends Equatable {
  const AuthenticationState._({
    this.status = AuthenticationStatus.unknown,
    this.user = User.empty,
  });

  const AuthenticationState.unknown() : this._();

  const AuthenticationState.authenticated(User user)
      : this._(status: AuthenticationStatus.authenticated, user: user);

  const AuthenticationState.unauthenticated()
      : this._(status: AuthenticationStatus.unauthenticated);

  final AuthenticationStatus status;
  final User user;

  @override
  List<Object> get props => [status, user];
}

这是一个命名的构造函数。在dart中,您可以通过两种方式定义构造函数,使用ClassNameClassName.someOtherName

EG:考虑你有一个名为2变量的人,名字和卡号。每个人都有名字,但卡号不是必需的。在这种情况下,如果您实现了默认构造函数,则必须对其进行初始化,如下所示:

Person("Name", "");
因此,如果您想添加一些语法糖,可以添加一个命名构造函数,如下所示:

class Person {
  String name;
  String carNumber;

  // Constructor creates a person with name & car number
  Person(this.name, this.carNumber);

  // Named constructor that only takes name and sets carNumber to ""
  Person.withOutCar(String name): this(name, "");

  // Named constructor with no arguments, just assigns "" to variables
  Person.unknown(): this("", "");
}
您可以初始化对象,如:

Person.withOutCar("Name");
在上面的示例中,命名的构造函数被重定向到实际的构造函数,并带有预定义的默认值

您可以在此处阅读有关命名构造函数的更多信息:

Person.withOutCar("Name");