Google apps script Google工作表未将行复制到正确的工作表

我使用电子邮件地址作为唯一标识符，将一张数据表拆分为多张数据表

我使用的是我找到并编辑过的脚本的变体，但使用的是copyTo而不是appendRow

问题在于，它似乎将特定数据集的最后一行复制到后续工作表中

  function myFunction() {
  
  var theWorkbook = SpreadsheetApp.getActiveSpreadsheet();
  var theSheet = theWorkbook.getSheetByName("Copied");
  
  // This var will contain all the values from column B -> The email addresses
  var theEmails = theSheet.getRange("B:B").getValues();

  // This var will contain all the rows
  var rows = theSheet.getDataRange().getValues();
  
  //Set the first row as the header
  var header = rows[0];

  //Store the Sheets already created
  var completedSheets = []

  //The last created Sheet
  var last = theEmails[1][0]


  for (var i = 1; i < theEmails.length; i++) {    

    //Check if the Sheet is already done, if not create the sheet
    if(!completedSheets.includes(theEmails[i][0])) {

      //Set the Sheet name = email address (except if there is no name, then = Blank)
      if (theEmails[i][0] === "") {
        var currentSheet = SpreadsheetApp.getActiveSpreadsheet().insertSheet("Blank");
      } else {
        var currentSheet = SpreadsheetApp.getActiveSpreadsheet().insertSheet(theEmails[i][0]);
      }


      //append the header
      currentSheet.appendRow(header);
      var rowtocopy = theSheet.getRange(i,1,1,8);
      rowtocopy.copyTo(currentSheet.getRange(currentSheet.getLastRow()+1, 1));
      completedSheets.push(theEmails[i][0])
      last = theEmails[i][0]
    } else if (last == theEmails[i][0]) {      
      
    // If the sheet is created append the row to the sheet
      var currentSheet = SpreadsheetApp.getActiveSpreadsheet();
      var activespreadsheet = SpreadsheetApp.getActiveSheet();
      var rowtocopy = theSheet.getRange(i,1,1,8);
      rowtocopy.copyTo(activespreadsheet.getRange(activespreadsheet.getLastRow()+1, 1));  
      
    }

  }
 

}

我想这可能是因为我使用的是getActiveSheet，而不是明确地针对正确的工作表，所以我尝试过这样做，使用类似于：getSheetByName（emailAddress[I][0]）的东西

然而，这一直是空的。当我记录emailaddress的值时，在记录器中查看，这些值显示正确，因此不太确定为什么会变为null

以下是“有效”的脚本，但将最后一行复制到后续工作表

  function myFunction() {
  
  var theWorkbook = SpreadsheetApp.getActiveSpreadsheet();
  var theSheet = theWorkbook.getSheetByName("Copied");
  
  // This var will contain all the values from column B -> The email addresses
  var theEmails = theSheet.getRange("B:B").getValues();

  // This var will contain all the rows
  var rows = theSheet.getDataRange().getValues();
  
  //Set the first row as the header
  var header = rows[0];

  //Store the Sheets already created
  var completedSheets = []

  //The last created Sheet
  var last = theEmails[1][0]


  for (var i = 1; i < theEmails.length; i++) {    

    //Check if the Sheet is already done, if not create the sheet
    if(!completedSheets.includes(theEmails[i][0])) {

      //Set the Sheet name = email address (except if there is no name, then = Blank)
      if (theEmails[i][0] === "") {
        var currentSheet = SpreadsheetApp.getActiveSpreadsheet().insertSheet("Blank");
      } else {
        var currentSheet = SpreadsheetApp.getActiveSpreadsheet().insertSheet(theEmails[i][0]);
      }


      //append the header
      currentSheet.appendRow(header);
      var rowtocopy = theSheet.getRange(i,1,1,8);
      rowtocopy.copyTo(currentSheet.getRange(currentSheet.getLastRow()+1, 1));
      completedSheets.push(theEmails[i][0])
      last = theEmails[i][0]
    } else if (last == theEmails[i][0]) {      
      
    // If the sheet is created append the row to the sheet
      var currentSheet = SpreadsheetApp.getActiveSpreadsheet();
      var activespreadsheet = SpreadsheetApp.getActiveSheet();
      var rowtocopy = theSheet.getRange(i,1,1,8);
      rowtocopy.copyTo(activespreadsheet.getRange(activespreadsheet.getLastRow()+1, 1));  
      
    }

  }
 

}

---

我做错了什么？

这是一个经典的表单，它的值数组是基于索引零的，API的“行”和“列”是基于索引一的

在

for

循环中，对

getRange（row，…）

调用中的值数组和API“row”参数使用相同的索引

i

。任何使用床单的人都会对自己这样做，可能已经很多次了

更新您的位置

var rowtopy=theSheet.getRange（i，1,1,8）；

到

var rowtopy=sheet.getRange（i+1,1,1,8）；

它会起作用的