Google bigquery 如何在BigQuery中显示多层次树结构
我正在研究主管及其受监管员工的树状层次结构。困难在于,有些主管是由其他主管监督的员工,而且数量很多 对于我从类中获得的SQL查询,只涉及简单的自联接,这可能只类似于两个级别:A由B监督,仅此而已 但现实世界的问题要复杂得多。有多个级别,我不确定确切的数字。例如,A由B监督,B由C监督,C由D监督,等等 我假设只有5个或更多级别的监管。原始数据可能如下所示:Google bigquery 如何在BigQuery中显示多层次树结构,google-bigquery,hierarchy,Google Bigquery,Hierarchy,我正在研究主管及其受监管员工的树状层次结构。困难在于,有些主管是由其他主管监督的员工,而且数量很多 对于我从类中获得的SQL查询,只涉及简单的自联接,这可能只类似于两个级别:A由B监督,仅此而已 但现实世界的问题要复杂得多。有多个级别,我不确定确切的数字。例如,A由B监督,B由C监督,C由D监督,等等 我假设只有5个或更多级别的监管。原始数据可能如下所示: Employee Supervisor A B C
Employee Supervisor
A B
C B
D B
B V
E V
F E
G V
V (Blank which indicates no boss)
H A
Row Supervisor Employee1 Employee2
1 V B A
2 V B C
3 V B D
4 V E F
5 V G null
一些BigQuery专家提供的代码如下:
#standardSQL
SELECT t.Supervisor,
IF(t.Supervisor = t5.Supervisor,
STRUCT(Employee2 AS Employee1, NULL AS Employee2),
STRUCT(t5.Supervisor AS Employee1, Employee2 AS Employee2)
).*
FROM (
SELECT t1.Employee Supervisor,
COALESCE(t4.Employee, t3.Employee, t2.Employee) Employee2
FROM `project.dataset.table` t1
LEFT JOIN `project.dataset.table` t2 ON t2.Supervisor = t1.Employee
LEFT JOIN `project.dataset.table` t3 ON t3.Supervisor = t2.Employee
LEFT JOIN `project.dataset.table` t4 ON t4.Supervisor = t3.Employee
WHERE t1.Supervisor IS NULL
) t
LEFT JOIN `project.dataset.table` t5 ON t5.Employee = t.Employee2
结果是这样的:
Employee Supervisor
A B
C B
D B
B V
E V
F E
G V
V (Blank which indicates no boss)
H A
Row Supervisor Employee1 Employee2
1 V B A
2 V B C
3 V B D
4 V E F
5 V G null
但我们想要的是:
Row Supervisor Employee1 Employee2 Employee3
1 V B A H
2 V B C Null
3 V B D Null
4 V E F Null
5 V G null Null
如果我想拥有更多层次结构,那么如何更改代码?也就是说,如果我想添加employee3或4,我如何编辑它?谢谢 下面是BigQuery标准SQL
#standardSQL
WITH e0 AS (
SELECT Employee AS Supervisor FROM `project.dataset.table` WHERE Supervisor IS NULL
), e1 AS (
SELECT e.Supervisor, Employee AS Employee1
FROM e0 e LEFT JOIN `project.dataset.table` t ON t.Supervisor = e.Supervisor
), e2 AS (
SELECT e.Supervisor, Employee1, Employee AS Employee2
FROM e1 e LEFT JOIN `project.dataset.table` t ON t.Supervisor = e.Employee1
), e3 AS (
SELECT e.Supervisor, Employee1, Employee2, Employee AS Employee3
FROM e2 e LEFT JOIN `project.dataset.table` t ON t.Supervisor = e.Employee2
)
SELECT * FROM e3
如果要应用于问题中的样本数据-结果/输出为
Row Supervisor Employee1 Employee2 Employee3
1 V B A H
2 V B C null
3 V B D null
4 V E F null
5 V G null null
您可以轻松地在上面扩展,添加更多级别,如下面(用相应的数字替换和,如4、5、6、7等),显然可以达到合理的扩展
e<N> AS (
SELECT e.Supervisor, Employee1, Employee2, Employee3, ... , Employee AS Employee<N>
FROM e<N-1> e LEFT JOIN `project.dataset.table` t ON t.Supervisor = e.Employee<N-1>
)
SELECT * FROM e<N>
它在理论上是有效的。但在我的实际工作表中,我发现一些员工没有被指派任何主管,这使得分析非常复杂。这很可能意味着你的初始数据不完整,或者有其他需要考虑的因素。因此,您可能需要重新审视您的案例并发布下一个新帖子/问题。同时,我认为你目前的问题已经完全解决了——考虑接受(如果还没有投票)-见下一篇文章:O)