Google sheets 查找使用同一JobID的用户

我只从Google电子表格中的每个用户表中提取JobID列。我想查询哪些用户正在使用相同的作业ID。我还需要将用户名列为查询的一列，因为该列不存在于每个用户工作表中，尽管工作表名称是用户名。有没有什么方法可以用谷歌查询做到这一点？ e、 g

另外，工作表可以重命名为其他用户。所以我们需要一些动态的东西

---

这里是到的链接。

是否需要以下工作？ 它动态地从用户选项卡中将工作表名称拉入“查询”。我认为您还需要首先从该用户选项卡中删除报告和用户名

这将出现在报告的C2中，目前需要向下拖动。我看看能不能想出一个公式

=TEXTJOIN(", ",1,
 {IF(COUNTIF(INDIRECT(USERS!A$1 & "!A$2:A"),A2),USERS!A$1,""), 
  IF(COUNTIF(INDIRECT(USERS!A$2 & "!A$2:A"),A2),USERS!A$2,""),
  IF(COUNTIF(INDIRECT(USERS!A$3 & "!A$2:A"),A2),USERS!A$3,""),
  IF(COUNTIF(INDIRECT(USERS!A$4 & "!A$2:A"),A2),USERS!A$4,""),
  IF(COUNTIF(INDIRECT(USERS!A$5 & "!A$2:A"),A2),USERS!A$5,""),
  IF(COUNTIF(INDIRECT(USERS!A$6 & "!A$2:A"),A2),USERS!A$6,"") })

=textjoin(", ",1,
 {if(countif(indirect(Users!A$1 & "!A$2:A"),A2),Users!A$1,""), 
  if(countif(indirect(Users!A$2 & "!A$2:A"),A2),Users!A$2,""),
  if(countif(indirect(Users!A$3 & "!A$2:A"),A2),Users!A$3,""),
  if(countif(indirect(Users!A$4 & "!A$2:A"),A2),Users!A$4,""),
  if(countif(indirect(Users!A$5 & "!A$2:A"),A2),Users!A$5,""),
  if(countif(indirect(Users!A$6 & "!A$2:A"),A2),Users!A$6,""), 
  if(countif(indirect(Users!A$7 & "!A$2:A"),A2),Users!A$7,""), 
  if(countif(indirect(Users!A$8 & "!A$2:A"),A2),Users!A$8,""), 
  if(countif(indirect(Users!A$9 & "!A$2:A"),A2),Users!A$9,""), 
  if(countif(indirect(Users!A$10 & "!A$2:A"),A2),Users!A$10,""),
  if(countif(indirect(Users!A$11 & "!A$2:A"),A2),Users!A$11,""),
  if(countif(indirect(Users!A$12 & "!A$2:A"),A2),Users!A$12,""),
  if(countif(indirect(Users!A$13 & "!A$2:A"),A2),Users!A$13,""),
  if(countif(indirect(Users!A$14 & "!A$2:A"),A2),Users!A$14,""),
  if(countif(indirect(Users!A$15 & "!A$2:A"),A2),Users!A$15,""),
  if(countif(indirect(Users!A$16 & "!A$2:A"),A2),Users!A$16,""),
  if(countif(indirect(Users!A$17 & "!A$2:A"),A2),Users!A$17,""),
  if(countif(indirect(Users!A$18 & "!A$2:A"),A2),Users!A$18,""),
  if(countif(indirect(Users!A$19 & "!A$2:A"),A2),Users!A$19,""),
  if(countif(indirect(Users!A$20 & "!A$2:A"),A2),Users!A$20,"")}) 

我只允许6个用户，但这可以扩展到处理10到20个用户，使用IF或IFERROR测试，以避免在任何时候用户选项卡中的用户数量较少时出现问题

如果你对此有任何疑问，请告诉我

更新#1 以下是允许20个用户使用的扩展公式。只要它们添加到用户的任何位置！A1:A20，并且图纸名称与其列出的名称匹配，则将包括其值。如果您发现任何问题，请告诉我。我还是会试着把它转换成一个数组公式

=TEXTJOIN(", ",1,
 {IF(COUNTIF(INDIRECT(USERS!A$1 & "!A$2:A"),A2),USERS!A$1,""), 
  IF(COUNTIF(INDIRECT(USERS!A$2 & "!A$2:A"),A2),USERS!A$2,""),
  IF(COUNTIF(INDIRECT(USERS!A$3 & "!A$2:A"),A2),USERS!A$3,""),
  IF(COUNTIF(INDIRECT(USERS!A$4 & "!A$2:A"),A2),USERS!A$4,""),
  IF(COUNTIF(INDIRECT(USERS!A$5 & "!A$2:A"),A2),USERS!A$5,""),
  IF(COUNTIF(INDIRECT(USERS!A$6 & "!A$2:A"),A2),USERS!A$6,"") })

=textjoin(", ",1,
 {if(countif(indirect(Users!A$1 & "!A$2:A"),A2),Users!A$1,""), 
  if(countif(indirect(Users!A$2 & "!A$2:A"),A2),Users!A$2,""),
  if(countif(indirect(Users!A$3 & "!A$2:A"),A2),Users!A$3,""),
  if(countif(indirect(Users!A$4 & "!A$2:A"),A2),Users!A$4,""),
  if(countif(indirect(Users!A$5 & "!A$2:A"),A2),Users!A$5,""),
  if(countif(indirect(Users!A$6 & "!A$2:A"),A2),Users!A$6,""), 
  if(countif(indirect(Users!A$7 & "!A$2:A"),A2),Users!A$7,""), 
  if(countif(indirect(Users!A$8 & "!A$2:A"),A2),Users!A$8,""), 
  if(countif(indirect(Users!A$9 & "!A$2:A"),A2),Users!A$9,""), 
  if(countif(indirect(Users!A$10 & "!A$2:A"),A2),Users!A$10,""),
  if(countif(indirect(Users!A$11 & "!A$2:A"),A2),Users!A$11,""),
  if(countif(indirect(Users!A$12 & "!A$2:A"),A2),Users!A$12,""),
  if(countif(indirect(Users!A$13 & "!A$2:A"),A2),Users!A$13,""),
  if(countif(indirect(Users!A$14 & "!A$2:A"),A2),Users!A$14,""),
  if(countif(indirect(Users!A$15 & "!A$2:A"),A2),Users!A$15,""),
  if(countif(indirect(Users!A$16 & "!A$2:A"),A2),Users!A$16,""),
  if(countif(indirect(Users!A$17 & "!A$2:A"),A2),Users!A$17,""),
  if(countif(indirect(Users!A$18 & "!A$2:A"),A2),Users!A$18,""),
  if(countif(indirect(Users!A$19 & "!A$2:A"),A2),Users!A$19,""),
  if(countif(indirect(Users!A$20 & "!A$2:A"),A2),Users!A$20,"")}) 

---

根据您的评论，我有一个公式来返回jobid和用户。但为了计算用户数量，我不得不添加另一列和公式。见下文：

D1中的关键公式如下：

={"Job ID","Users (hidden)";
  ArrayFormula(trim(split(regexreplace(REGEXREPLACE(transpose(query(query({
     query({ Users!A$1 & "♦️" & row(indirect(Users!A$1 & "!A$2:A")), indirect(Users!A$1 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$2 & "♦️" & row(indirect(Users!A$2 & "!A$2:A")), indirect(Users!A$2 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$3 & "♦️" & row(indirect(Users!A$3 & "!A$2:A")), indirect(Users!A$3 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$4 & "♦️" & row(indirect(Users!A$4 & "!A$2:A")), indirect(Users!A$4 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$5 & "♦️" & row(indirect(Users!A$5 & "!A$2:A")), indirect(Users!A$5 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$6 & "♦️" & row(indirect(Users!A$6 & "!A$2:A")), indirect(Users!A$6 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0) },
     "select max(Col1) where Col2 <>'' group by Col1 pivot Col2",0)
     ,,99^99)),
     "♦️[0-9 ]+" , ", "),
     "(.*),", "$1"),
     "♥️",0)))}

如果

用户中的任何一个出现错误，则给我一个错误！A2

为空，或单元格

用户中没有与名称匹配的选项卡！A2

、或具有该名称的选项卡没有数据

如果您采取这些措施，那么主公式可以预设为处理二十个（或更多）用户。我上面展示的公式适用于当前的六个用户，但我已经用更多的方法进行了测试。我将在底部为20个用户提供公式

让我知道这是否有帮助，或者如果你有问题。很高兴回答他们

20个用户的公式。在用户中，每个“用户”都有一个名称或虚拟名称占位符，必须有一个具有该名称的选项卡，并且每个选项卡中必须至少有一个JobID值，或者一个虚拟JobID，可能类似于99999

={"Job ID","Users (hidden)";
  ArrayFormula(trim(split(regexreplace(REGEXREPLACE(transpose(query(query({
     query({ Users!A$1 & "♦️" & row(indirect(Users!A$1 & "!A$2:A")), indirect(Users!A$1 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$2 & "♦️" & row(indirect(Users!A$2 & "!A$2:A")), indirect(Users!A$2 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$3 & "♦️" & row(indirect(Users!A$3 & "!A$2:A")), indirect(Users!A$3 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$4 & "♦️" & row(indirect(Users!A$4 & "!A$2:A")), indirect(Users!A$4 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$5 & "♦️" & row(indirect(Users!A$5 & "!A$2:A")), indirect(Users!A$5 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$6 & "♦️" & row(indirect(Users!A$6 & "!A$2:A")), indirect(Users!A$6 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$7 & "♦️" & row(indirect(Users!A$7 & "!A$2:A")), indirect(Users!A$7 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$8 & "♦️" & row(indirect(Users!A$8 & "!A$2:A")), indirect(Users!A$8 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$9 & "♦️" & row(indirect(Users!A$9 & "!A$2:A")), indirect(Users!A$9 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$10 & "♦️" & row(indirect(Users!A$10 & "!A$2:A")), indirect(Users!A$10 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$11 & "♦️" & row(indirect(Users!A$11 & "!A$2:A")), indirect(Users!A$11 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$12 & "♦️" & row(indirect(Users!A$12 & "!A$2:A")), indirect(Users!A$12 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$13 & "♦️" & row(indirect(Users!A$13 & "!A$2:A")), indirect(Users!A$13 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$14 & "♦️" & row(indirect(Users!A$14 & "!A$2:A")), indirect(Users!A$14 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$15 & "♦️" & row(indirect(Users!A$15 & "!A$2:A")), indirect(Users!A$15 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$16 & "♦️" & row(indirect(Users!A$16 & "!A$2:A")), indirect(Users!A$16 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$17 & "♦️" & row(indirect(Users!A$17 & "!A$2:A")), indirect(Users!A$17 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$18 & "♦️" & row(indirect(Users!A$18 & "!A$2:A")), indirect(Users!A$18 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$19 & "♦️" & row(indirect(Users!A$19 & "!A$2:A")), indirect(Users!A$19 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A$20 & "♦️" & row(indirect(Users!A$20 & "!A$2:A")), indirect(Users!A$20 & "!A$2:A")&"♥️"}, "where Col2<> '♥️'",0) },
     "select max(Col1) where Col2 <>'' group by Col1 pivot Col2",0)
     ,,99^99)),
     "♦️[0-9 ]+" , ", "),
     "(.*),", "$1"),
     "♥️",0)))}

={“作业ID”，“用户（隐藏）”；
数组公式（trim）（split）（regexreplace）（regexreplace）（transpose）（查询({
查询（{Users！A$1&“♦️" & 行（间接（用户！A$1&“！A$2:A”）、间接（用户！A$1&“！A$2:A”）&”♥️“}”，Col2'♥️'",0);
查询（{Users！A$2&“♦️&row（间接（用户！A$2&“！A$2:A”）、间接（用户！A$2&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$3&“♦️&row（间接（用户！A$3&“！A$2:A”）、间接（用户！A$3&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$4&“♦️&row（间接（用户！A$4&“！A$2:A”）、间接（用户！A$4&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$5&“♦️&row（间接（用户！A$5&“！A$2:A”）、间接（用户！A$5&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$6&“♦️&row（间接（用户！A$6&“！A$2:A”）、间接（用户！A$6&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$7&“♦️&row（间接（用户！A$7&“！A$2:A”）、间接（用户！A$7&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$8&“♦️&row（间接（用户！A$8&“！A$2:A”）、间接（用户！A$8&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$9&“♦️&row（间接（用户！A$9&“！A$2:A”）、间接（用户！A$9&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$10&“♦️&row（间接（用户！A$10&“！A$2:A”）、间接（用户！A$10&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$11&“♦️&row（间接（用户！A$11&“！A$2:A”）、间接（用户！A$11&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$12&“♦️&row（间接（用户！A$12&“！A$2:A”）、间接（用户！A$12&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$13&“♦️&row（间接（用户！A$13&“！A$2:A”）、间接（用户！A$13&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$14&“♦️&row（间接（用户！A$14&“！A$2:A”）、间接（用户！A$14&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$15&“♦️&row（间接（用户！A$15&“！A$2:A”）、间接（用户！A$15&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$16&“♦️&row（间接（用户！A$16&“！A$2:A”）、间接（用户！A$16&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$17&“♦️&row（间接（用户！A$17&“！A$2:A”）、间接（用户！A$17&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$18&“♦️&row（间接（用户！A$18&“！A$2:A”）、间接（用户！A$18&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$19&“♦️&row（间接（用户！A$19&“！A$2:A”）、间接（用户！A$19&“！A$2:A”）&♥️“}”，Col2'♥️'",0);
查询（{Users！A$20&“♦️&row（间接（用户！A$20&“！A$2:A”）、间接（用户！A$20&“！A$2:A”）&♥️“}”，Col2'♥️'",0) },
“选择最大值（Col1），其中Col2”“按Col1枢轴Col2分组”，0）
,,99^99)),
"♦️[0-9 ]+" , ", "),
"(.*),", "$1"),
"♥️",0)))}

输入数据的描述也会很有帮助，不仅仅是输出数据。另外，请分享您迄今为止的尝试：@mshcruz当然。给我几分钟。我将分享一个电子表格。大约有多少用户，我的意思是有多少不同的谷歌表格？不超过10-12个，但JobID将是应用程序从6k到10k。具体来说，需要一个Google查询，而不是appscript.Als