grailsgorm:选择为
我试图获取所有今天出生于GORM的用户,但我无法在Grails中编写此查询:grailsgorm:选择为,grails,gorm,Grails,Gorm,我试图获取所有今天出生于GORM的用户,但我无法在Grails中编写此查询: SELECT DAY(dateOfBirth) AS 'day', MONTH(dateOfBirth) AS 'month' FROM Users WHERE day = '...' AND month = '...'; …将替换为今天的值 最小用户域类 class User { Date dateOfBirth ... } @Transactional class UserService {
SELECT
DAY(dateOfBirth) AS 'day',
MONTH(dateOfBirth) AS 'month'
FROM Users
WHERE day = '...' AND month = '...';
…
将替换为今天的值
最小用户
域类
class User {
Date dateOfBirth
...
}
@Transactional
class UserService {
def getTodayBirthdays() {
def bornTodayQuery = User.where{
/* I'm thinking here I must
* select the DAY and MONTH from the DB
* and compare it with the today ones.
*/
}
User usersBornToday = bornTodayQuery.findAll()
usersBornToday
}
}
最小UserService
class
class User {
Date dateOfBirth
...
}
@Transactional
class UserService {
def getTodayBirthdays() {
def bornTodayQuery = User.where{
/* I'm thinking here I must
* select the DAY and MONTH from the DB
* and compare it with the today ones.
*/
}
User usersBornToday = bornTodayQuery.findAll()
usersBornToday
}
}
有没有办法用GORM做一个别名(选择字段作为别名)
我正在使用:
- Grails2.4.4
谢谢您可以在服务中使用where查询:
@Transactional(readOnly = true)
def listBirthday(int _month, int _day) {
// Calendar.JANUARY equals to zero!
def m = _month + 1
// Run a where query on the users
User.where {
month(dateOfBirth) == m && day(dateOfBirth) == _day
}
}
@Transactional(readOnly = true)
def listBirthdayToday() {
def cal = Calendar.getInstance()
listBirthday(cal.get(cal.MONTH), cal.get(cal.DAY_OF_MONTH))
}
除了
月
和日
还有一些其他功能,文档(查找“其他功能”)是否回答了您的问题@有点像sebnukem,但我正在寻找一种不使用executeQuery
的方法。“当然,如果它存在的话。我不认为你可以和戈姆在一起,但我可能错了…”塞布努金显然你可以,同意铍的回答。谢谢