Groovy 修改zipfile条目的文件内容

Groovy 修改zipfile条目的文件内容,groovy,zipfile,Groovy,Zipfile,我想更新zipfile中文本文件的内容 我无法找到如何做到这一点,下面的代码工作不正常 谢谢你的帮助 import java.util.zip.ZipFile import java.util.zip.ZipEntry import java.util.zip.ZipOutputStream String zipFileFullPath = "C:/path/to/myzipfile/test.zip" ZipFile zipFile = new ZipFile(zipFileFullPat

我想更新zipfile中文本文件的内容

我无法找到如何做到这一点,下面的代码工作不正常

谢谢你的帮助

import java.util.zip.ZipFile
import java.util.zip.ZipEntry
import java.util.zip.ZipOutputStream

String zipFileFullPath = "C:/path/to/myzipfile/test.zip"

ZipFile zipFile = new ZipFile(zipFileFullPath) 
ZipEntry entry = zipFile.getEntry ( "someFile.txt" )

if(entry){
    InputStream input = zipFile.getInputStream(entry)
    BufferedReader br = new BufferedReader(new InputStreamReader(input, "UTF-8"))

    String s = null
    StringBuffer sb = new StringBuffer()

    while ((s=br.readLine())!=null){
         sb.append(s)
    }

    sb.append("adding some text..")


     ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFileFullPath))
     out.putNextEntry(new ZipEntry("someFile.txt"));

     int length


     InputStream fin = new ByteArrayInputStream(sb.toString().getBytes("UTF8"))

     while((length = fin.read(sb)) > 0)
     {
            out.write(sb, 0, length)
     }             

     out.closeEntry()

}

到底是什么不起作用?是否引发了任何异常

据我所知,不可能在原地修改zip文件。下面的脚本重写文件,如果处理了所需的条目,则对其进行修改

import java.util.zip.*

def zipIn = new File('lol.zip')
def zip = new ZipFile(zipIn)
def zipTemp = File.createTempFile('out', 'zip')
zipTemp.deleteOnExit()
def zos = new ZipOutputStream(new FileOutputStream(zipTemp))
def toModify = 'lol.txt'

for(e in zip.entries()) {
    if(!e.name.equalsIgnoreCase(toModify)) {
        zos.putNextEntry(e)
        zos << zip.getInputStream(e).bytes
    } else {
        zos.putNextEntry(new ZipEntry(toModify))
        zos << 'lollol\n'.bytes
    }
    zos.closeEntry()
}

zos.close()
zipIn.delete()
zipTemp.renameTo(zipIn)

对@Opal的答案稍作修改,我只是:

  • 尽可能使用groovy方法
  • 打包在方法中
Groovy代码段

void updateZipEntry(字符串zipFile、字符串zipEntry、字符串newContent){
def zin=新ZipFile(ZipFile)
def tmp=File.createTempFile(“temp_${System.nanoTime()},'.zip'))
tmp.withOutputStream{os->
def zos=新ZipoutStream(操作系统)
zin.entries()。每个{entry->
def isReplaced=entry.name==zipEntry
zos.Putnextry(被替换?新ZipEntry(ZipEntry):条目)

zos感谢您对Opal的帮助。您的第一个解决方案看起来很棒,但由于某些原因,没有发生任何变化,zipfile似乎根本没有被更改。zip文件没有被删除。临时文件看起来不错。我已经在Mac OS上进行了测试。请让我知道它是否解决了问题。我可以再次检查。zipIn.delete()返回false,不知道为什么无法删除此文件。在调用delete()之前,该文件仍被代码锁定。为什么?
import java.util.zip.*

def zipFileFullPath = 'lol.zip'
def zipFile = new ZipFile(zipFileFullPath) 
def entry = zipFile.getEntry('lol.txt')

if(entry) {
   def input = zipFile.getInputStream(entry)
   def br = new BufferedReader(new InputStreamReader(input, 'UTF-8'))
   def sb = new StringBuffer()

   sb << br.text
   sb << 'adding some text..'

   def out = new ZipOutputStream(new FileOutputStream(zipFileFullPath))
   out.putNextEntry(new ZipEntry('lol.txt'))

   out << sb.toString().getBytes('UTF8')
   out.closeEntry()
   out.close()
}
void updateZipEntry(String zipFile, String zipEntry, String newContent){
    def zin = new ZipFile(zipFile)
    def tmp = File.createTempFile("temp_${System.nanoTime()}", '.zip')
    tmp.withOutputStream { os ->
        def zos = new ZipOutputStream(os)
        zin.entries().each { entry ->
            def isReplaced = entry.name == zipEntry
            zos.putNextEntry(isReplaced ? new ZipEntry(zipEntry) : entry)
            zos << (isReplaced ? newContent.getBytes('UTF8') : zin.getInputStream(entry).bytes )
            zos.closeEntry()
        }
        zos.close()
    }
    zin.close()
    assert new File(zipFile).delete()
    tmp.renameTo(zipFile)
}
updateZipEntry('/tmp/file.zip', 'META-INF/web.xml', '<foobar>new content!</foobar>')