如何将任意参数传递给包装的groovy函数?
我有一个groovy包装函数,我想将任意参数传递给包装方法调用 例如:如何将任意参数传递给包装的groovy函数?,groovy,wrapper,keyword-argument,Groovy,Wrapper,Keyword Argument,我有一个groovy包装函数,我想将任意参数传递给包装方法调用 例如: // Arguments: appliance, temperature, duration def cook(Map args = [:]) { print(args.appliance) print(args.temperature) print(args.duration) } // Arguments: appliance, plus whatever arguments cook() ha
// Arguments: appliance, temperature, duration
def cook(Map args = [:]) {
print(args.appliance)
print(args.temperature)
print(args.duration)
}
// Arguments: appliance, plus whatever arguments cook() has
def cookWithKitchenAid(Map cookArgs = [:]) {
cook(appliance: "KitchenAid " + cookArgs.appliance, cookArgs)
}
cookWithKitchenAid(appliance: "oven", temperature: "300", duration: "60")
Python有一种传递任意关键字参数的方法,请参见。groovy中的等价物是什么?您的意思是这样的<代码>厨具(cookArgs+[appliance:“KitchenAid”+cookArgs.appliance])是。谢谢,你是说像这样<代码>厨具(cookArgs+[appliance:“KitchenAid”+cookArgs.appliance])是。非常感谢。