Haskell中的语法错误

我在编译Haskell脚本时出错。请帮助：

main = do
let bmiTell weight height
    | weight / height ^ 2 <= 18.5 = "You're underweight, you emo, you!"
    | weight / height ^ 2 <= 25.0 = "You're supposedly normal. Pffft, I bet you're ugly!"
    | weight / height ^ 2 <= 30.0 = "You're fat! Lose some weight, fatty!"
    | otherwise                   = "You're a whale, congratulations!"                = "You're a whale, congratulations!"

main=do
让我告诉你体重和身高
|体重/身高^2两个问题


如注释中所述，您的防护装置至少需要缩进一个额外的空间（因此管道比
b
缩进得更多）

在
do
块中，您需要的不仅仅是
let
。例如，您可能想要测试您的函数


解决了这些问题后：

main = do
  let bmiTell weight height
       | weight / height ^ 2 <= 18.5 = "You're underweight, you emo, you!"
       | weight / height ^ 2 <= 25.0 = "You're supposedly normal. Pffft, I bet you're ugly!"
       | weight / height ^ 2 <= 30.0 = "You're fat! Lose some weight, fatty!"
       | otherwise                   = "You're a whale, congratulations!"  
  putStrLn $ bmiTell 6 1

main=do
让我告诉你体重和身高
|重量/高度^2我认为防护罩中的
|
需要缩进，超过
bmiTell中的
b
。向右滚动。那个多余的东西在那里干什么？