Haskell中的泛型序列化
我在尝试反序列化对象时遇到此错误Haskell中的泛型序列化,haskell,serialization,deserialization,Haskell,Serialization,Deserialization,我在尝试反序列化对象时遇到此错误 Amy64.hs: GetException "too few bytes\nFrom:\tdemandInput\n\n" 将创建输出文件,如下所示: 00000000 1f 8b 08 00 00 00 00 00 04 03 63 60 00 03 56 a7 |..........c`..V.| 00000010 d2 f4 e2 4a 00 be b2 38 41 0d 00 00 00 |...J...8A....|
Amy64.hs: GetException "too few bytes\nFrom:\tdemandInput\n\n"
将创建输出文件,如下所示:
00000000 1f 8b 08 00 00 00 00 00 04 03 63 60 00 03 56 a7 |..........c`..V.|
00000010 d2 f4 e2 4a 00 be b2 38 41 0d 00 00 00 |...J...8A....|
我怀疑我没有正确使用新的泛型。这是我的密码。顺便说一下,如果我删除第9行、第22行和第23行,我会得到相同的结果。如果我删除gzip/ungzip内容,我会得到相同的结果
{-# LANGUAGE DeriveGeneric #-}
import Data.Conduit (runResourceT, ($$), (=$))
import Data.Conduit.Binary (sinkFile, sourceFile)
import Data.Conduit.Cereal (sinkGet, sourcePut)
import Data.Conduit.Zlib (gzip, ungzip)
import qualified Data.Serialize as DS (Serialize, get, put)
import GHC.Generics (Generic)
import Data.Serialize.Derive (derivePut, deriveGet) -- line 9
readBug :: FilePath -> IO (Either String Bug)
readBug f =
runResourceT $ sourceFile f $$ ungzip =$ sinkGet (DS.get)
writeBug :: FilePath -> Bug -> IO ()
writeBug f t =
runResourceT $ sourcePut (DS.put t) $$ gzip =$ sinkFile f
data Bug = Bug String deriving (Show, Generic)
instance DS.Serialize Bug where
put = derivePut -- line 22
get = deriveGet -- line 23
main = do
let a = Bug "Bugsy"
writeBug "x.dat" a
(Right b) <- readBug "x.dat" :: IO (Either String Bug)
print b
{-#派生通用语言}
导入数据.conduction(runResourceT,($$),(=$))
导入Data.conductor.Binary(sinkFile、sourceFile)
导入Data.conductor.graines(sinkGet、sourcePut)
导入Data.conductor.Zlib(gzip,ungzip)
导入符合条件的数据。序列化为DS(序列化、获取、放置)
进口GHC.仿制药(仿制药)
导入Data.Serialize.Derive(derivePut,deriveGet)--第9行
readBug::FilePath->IO(任一字符串错误)
readBug f=
runResourceT$sourceFile f$$ungzip=$sinkGet(DS.get)
writeBug::文件路径->错误->IO()
writeBug f t=
runResourceT$sourcePut(DS.put t)$$gzip=$sinkFile f
数据错误=错误字符串派生(显示,通用)
实例DS。序列化错误,其中
put=派生put--第22行
get=deriveGet——第23行
main=do
让a=Bug“Bugsy”
写下bug“x.dat”a
(右b)事实证明,我的错误与泛型本身无关。readBug
函数上的错误类型签名导致它尝试读取字符串Bug
,而不仅仅是Bug
{-# LANGUAGE DeriveGeneric #-}
import Data.Conduit (runResourceT, ($$), (=$))
import Data.Conduit.Binary (sinkFile, sourceFile)
import Data.Conduit.Cereal (sinkGet, sourcePut)
import Data.Conduit.Zlib (gzip, ungzip)
import qualified Data.Serialize as DS (Serialize, get, put)
import GHC.Generics (Generic)
import Data.Serialize.Derive (derivePut, deriveGet) -- line 9
readBug :: FilePath -> IO Bug
readBug f =
runResourceT $ sourceFile f $$ ungzip =$ sinkGet DS.get
writeBug :: FilePath -> Bug -> IO ()
writeBug f t =
runResourceT $ sourcePut (DS.put t) $$ gzip =$ sinkFile f
data Bug = Bug String deriving (Show, Generic)
instance DS.Serialize Bug where
put = derivePut -- line 22
get = deriveGet -- line 23
main :: IO ()
main = do
let a = Bug "Bugsy"
writeBug "x.dat" a
b <- readBug "x.dat" :: IO Bug
print b
{-#派生通用语言}
导入数据.conduction(runResourceT,($$),(=$))
导入Data.conductor.Binary(sinkFile、sourceFile)
导入Data.conductor.graines(sinkGet、sourcePut)
导入Data.conductor.Zlib(gzip,ungzip)
导入符合条件的数据。序列化为DS(序列化、获取、放置)
进口GHC.仿制药(仿制药)
导入Data.Serialize.Derive(derivePut,deriveGet)--第9行
readBug::文件路径->IO错误
readBug f=
runResourceT$sourceFile f$$ungzip=$sinkGet DS.get
writeBug::文件路径->错误->IO()
writeBug f t=
runResourceT$sourcePut(DS.put t)$$gzip=$sinkFile f
数据错误=错误字符串派生(显示,通用)
实例DS。序列化错误,其中
put=派生put--第22行
get=deriveGet——第23行
main::IO()
main=do
让a=Bug“Bugsy”
写下bug“x.dat”a
B