Hibernate条件在SQLite中不起作用
我的装备：Hibernate条件在SQLite中不起作用,hibernate,sqlite,Hibernate,Sqlite,我的装备： 休眠3.6.9 Hibernate SQLite方言来自 我的实体类很简单 @Entity @Table(name = "RegistrationRequests") public class RegistrationRequest { @Id @GeneratedValue Integer id; String uuid; ... getters and setters ... } uuid被分配给uuid.randomUUID（）.
- 休眠3.6.9
- Hibernate SQLite方言来自
@Entity
@Table(name = "RegistrationRequests")
public class RegistrationRequest {
@Id
@GeneratedValue
Integer id;
String uuid;
... getters and setters ...
}
Criteria criteria = sessionFactory.getCurrentSession().createCriteria(RegistrationRequest.class);
criteria.add(Restrictions.eq("uuid", '\'' + uuid + '\''));
List requests = criteria.list();
select
this_.id as id2_0_,
this_.created as created2_0_,
this_.email as email2_0_,
this_.isVerified as isVerified2_0_,
this_.name as name2_0_,
this_.password as password2_0_,
this_.surname as surname2_0_,
this_.uuid as uuid2_0_
from
RegistrationRequests this_
where
this_.uuid='ced61d13-f5a7-4c7e-a047-dd6f066d8e67'
我有点困惑，尝试了所有的方法都没有结果…据我所知，就hibernate api而言，您不必自己设置where子句的值（我使用Nhibernate），因此当您将where子句的值设置为“myValue”时，您实际上是在搜索字符串，以匹配“myValue”，在您想要的位置搜索myValue 更改此选项有望使其正常工作：
Criteria criteria = sessionFactory.getCurrentSession().createCriteria(RegistrationRequest.class);
criteria.add(Restrictions.eq("uuid", uuid));
List requests = criteria.list();
'\''+uuid+'\''