Hibernate hql join@CollectionTable
我有一个域名Hibernate hql join@CollectionTable,hibernate,hql,jpql,Hibernate,Hql,Jpql,我有一个域名服务,上面有收藏标签,如下所示: @Entity public class Service extends AbstractEntity<Long> { private static final long serialVersionUID = 9116959642944725990L; @ElementCollection(fetch = FetchType.EAGER, targetClass = java.lang.Strin
服务
,上面有收藏标签
,如下所示:
@Entity
public class Service extends AbstractEntity<Long> {
private static final long serialVersionUID = 9116959642944725990L;
@ElementCollection(fetch = FetchType.EAGER, targetClass = java.lang.String.class)
@CollectionTable(name = "service_tags", joinColumns = @JoinColumn(name = "s_id"))
@Column(name = "tag")
private Set<String> tags;
}
select s from Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College'))
Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: cannot dereference scalar collection element: tag [select s from com.zazzercode.domain.Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College')) ]
Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: null near line 1, column 188 [select s from com.esewa.server.entity.Service s where s.status=0 and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))]
但是,上面的hql返回我,但有以下异常:
@Entity
public class Service extends AbstractEntity<Long> {
private static final long serialVersionUID = 9116959642944725990L;
@ElementCollection(fetch = FetchType.EAGER, targetClass = java.lang.String.class)
@CollectionTable(name = "service_tags", joinColumns = @JoinColumn(name = "s_id"))
@Column(name = "tag")
private Set<String> tags;
}
select s from Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College'))
Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: cannot dereference scalar collection element: tag [select s from com.zazzercode.domain.Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College')) ]
Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: null near line 1, column 188 [select s from com.esewa.server.entity.Service s where s.status=0 and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))]
从服务的内部连接s.t中选择s,其中s.status=0
起作用
看着,我试着像下面这样
"select s from Service s where s.status=0 and s.priviligedUser.priviligedUserType IN (2,4) and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))"
出现以下异常:
@Entity
public class Service extends AbstractEntity<Long> {
private static final long serialVersionUID = 9116959642944725990L;
@ElementCollection(fetch = FetchType.EAGER, targetClass = java.lang.String.class)
@CollectionTable(name = "service_tags", joinColumns = @JoinColumn(name = "s_id"))
@Column(name = "tag")
private Set<String> tags;
}
select s from Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College'))
Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: cannot dereference scalar collection element: tag [select s from com.zazzercode.domain.Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College')) ]
Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: null near line 1, column 188 [select s from com.esewa.server.entity.Service s where s.status=0 and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))]
几个月前我也取得了同样的成就。多亏了
下面的代码工作!!!
这个被接受的答案对我来说并不适用,因为这个值只适用于地图,但这里是一个集合。