Hibernate 嵌套复合键

我有以下两个实体的组合键

@Embeddable
public class ProductId implements Serializable {
    @Column(name = "Id", columnDefinition = "bigint identity(1,1)")
    private Long id;

    @Column(name = "ProductTypeName")
    private String name;
....
}

@Embeddable
public class ApplicationId implements Serializable{
    @Column(name = "Id", columnDefinition = "bigint identity(1,1)",
            nullable = false, insertable = false, updatable = false)
    private Long id;
    @Embedded
    @AttributeOverride(name="id",
                       column=@Column(name="ProductId",
                                  columnDefinition = "bigint identity(1,1)",
                                  nullable = false, insertable = false,
                                  updatable = false))
    private ProductId productId;
....
}

我有两个不同的实体，都具有上面定义的复合键。我的问题是嵌套复合键，我正试图让它工作，但当hibernate扫描以ApplicationId Embbable对象作为其PK的实体时，它失败了（下面是给出问题的实体的映射）

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Hibernate抱怨出现以下错误

，原因是：org.Hibernate.MappingException:在应用程序中找不到逻辑名称为ProductId的列

对于任何有此问题的人，最好使用IdClass方法。此外，我认为这是一种更好的方法，因为参与复合id的所有实体都用@id注释，代码更可读、更容易理解。如果有人需要一个例子，让我知道我会张贴答案。

@Entity(name = "Application")
@Table(name = "Application")
@Inheritance(strategy = InheritanceType.JOINED)
public abstract class Application {

    @EmbeddedId
    private ApplicationId applicationPk;

    @MapsId("productId")
    @ManyToOne(fetch = FetchType.LAZY, optional = false)
    @JoinColumns({@JoinColumn(name = "ProductId", referencedColumnName = "Id",
                           nullable = false, insertable = true,
                           updatable = true),
                  @JoinColumn(name = "ProductTypeName",
                           referencedColumnName = "ProductTypeName",
                           nullable = false, insertable = true,
                           updatable = true)})
    @ForeignKey(name = "FK_Application_Product")
    private Product product;
....}