Html 如何指定每个角度树根节点的子节点的链接或函数?
如何指定每个角度树根节点的子节点的链接或函数 .html的示例Html 如何指定每个角度树根节点的子节点的链接或函数?,html,angular,typescript,tree,nodes,Html,Angular,Typescript,Tree,Nodes,如何指定每个角度树根节点的子节点的链接或函数 .html的示例 <!-- edited after advise from @SachilaRanawaka, somehow (onToggle) is not having any reactions but (click) has--> <tree-root #tree [nodes]="nodes" (click)="handleEvent($event)"></tree-root> 如何指定链
<!-- edited after advise from @SachilaRanawaka,
somehow (onToggle) is not having any reactions
but (click) has-->
<tree-root #tree [nodes]="nodes" (click)="handleEvent($event)"></tree-root>
如何指定链接,例如a href?路由器?或在单击children1或children2时运行的函数
有房子吗
大致是这样的:
nodes = [{id:1,name:"parent",children:[
{id:2,name:"children1", link:"/test/children1.html" },
{id:3,name:"children2", link:"/test/children2.html" }
]
}];
这里有一个关于我使用的树类型的链接:好的,我已经找到了解决上述问题的方法 所以我只是想和大家分享一下。这是 这样做的目的是获取没有子节点的节点的名称,并对其进行处理。使其可点击 通常,可单击的节点应该是最后一个展开的节点 在下面的示例中,我给了它一个函数来调用带有节点名的警报 更新了.HTML以使用ng模板 因此,输出:
> parent <--- not clickable
> children1 <--- clickable and generated alert box
> children2 <--- clickable and generated alert box
是什么?如果这是您的自定义组件,我们如何知道是否存在属性?链接或函数应该做什么?@GünterZöchbauer,抱歉,我已经包含了一个指向我所指的angular2树的链接。你不能使用事件来调用函数@SachilaRanawaka,嗯,听起来很有趣。。这只处理孩子们吗?使用$event.eventName
<tree-root #tree [nodes]="nodes">
<ng-template #treeNodeTemplate let-node>
<!--For node with no children(last node), give it a function/link-->
<div *ngIf="!node.data.children">
<span (click)="doSomething(node.data.name)">{{ node.data.name }}</span>
</div>
<!--For node with children, don't need a link, all it needs to do is to just expand-->
<div *ngIf="node.data.children">
<span>{{ node.data.name }}</span>
</div>
</ng-template>
</tree-root>
nodes = [{id:1,name:"parent",children:[
{id:2,name:"children1"},
{id:3,name:"children2"}
]
}];
doSomething(nodeName){
alert(nodeName);
}
> parent <--- not clickable
> children1 <--- clickable and generated alert box
> children2 <--- clickable and generated alert box