Hybris 没有名为“myJobPerformable”的bean可用

我正在尝试从backoffice向导处理程序执行cronjob

CronJob项在mybackoffice-items.xml、myCronJob中定义 作业可执行bean在mybackoffice-backoffice-spring.xml、myJobPerformable中定义 向导处理程序bean在mybackoffice-backoffice-spring.xml、myHandler中定义 myHandler从其执行函数调用executeJob：

  private void executeJob() {
    String springId = "myJobPerformable";
    String id = springId;
    JobModel myJob = getJob(springId).orElseGet(createJob(id, springId));
    id = String.valueOf(this.keyGenerator.generate());
    CronJobModel myCronJob = createCronJob(id, myJob);
    this.cronJobService.performCronJob(myCronJob);
  }

  private Optional<JobModel> getJob(String springId) {
    ServicelayerJobModel myJob = new ServicelayerJobModel();
    myJob.setSpringId(springId);
    try {
      return Optional.ofNullable(flexibleSearchService.getModelByExample(myJob));
    } catch (ModelNotFoundException e) {
      return Optional.empty();
    }
  }

  private Supplier<JobModel> createJob(String id, String springId) {
    return () -> {
      ServicelayerJobModel myJob = modelService.create(ServicelayerJobModel.class);
      myJob.setCode(id);
      myJob.setSpringId(springId);
      modelService.save(myJob);
      return myJob;
    };
  }

  private MyCronJobModel createCronJob(String id, JobModel myJob) {
    MyCronJobModel myCronJob = this.modelService.create(MyCronJobModel.class);
    myCronJob.setCode(id);
    myCronJob.setActive(Boolean.TRUE);
    myCronJob.setJob(myJob);
    myCronJob.setSessionUser(this.userService.getCurrentUser());
    myCronJob.setSessionLanguage(this.commonI18NService.getCurrentLanguage());
    myCronJob.setSessionCurrency(this.commonI18NService.getCurrentCurrency());
    this.modelService.save(myCronJob);
    return myCronJob;
  }

问题发生在该代码运行时，它不会抛出名为“myJobPerformable”的bean。

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但是，该bean已经在mybackoffice backoffice spring中注册。xml

似乎将您的bean定义从mybackoffice-backoffice-spring.xml移动到mybackoffice-spring.xml应该会修复它，因为您的bean将注册到应用程序上下文中，并可用于服务层

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希望有帮助

似乎将bean定义从mybackoffice-backoffice-spring.xml移动到mybackoffice-spring.xml应该可以解决这个问题，因为您的bean将被注册到应用程序上下文中，并可用于服务层

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希望有帮助

很高兴它有帮助！很高兴它有帮助！