Ios JSON解析：从NSDictionary检索数据并将其存储在数组中

我正在尝试从JSON字典中检索数据。 我需要从地址字典中获取地址中的数据并将其存储在数组中。 我的数组应该如下所示： [印度，班加罗尔，卡纳塔克邦560008，印度，班加罗尔，卡纳塔克邦560008，印度，班加罗尔，卡纳塔克邦560008，印度，马哈拉施特拉邦，孟买，瓦达拉，瓦达拉村19号公路256号，印度，400031]

我需要帮助

您可以使用NSPredicate筛选NSDictionary

假设你的字典是NSDictionary*dict

---

你检查过nsjsonserialization类及其方法了吗？好吧，你不只是创建一个NSMutableArray并从字典中添加你想要的东西吗？正如我所看到的，你的JSON数组是不正确的。地址缺少双引号，JSON数组中不应该有分号。谢谢Jad。但它仍然不工作，事实上它以零值崩溃。它在哪里崩溃？尝试记录pR、pArray和dict。让我知道发生了什么[resultArray addObject:dict[@address]]；resultArray返回nil你能在循环中记录dict[@address]并告诉我你得到了什么吗？任何时候都没有问题：D，只需提交有效的答案，让人们知道你得到了回答：D

{
    Address =     (
                {
            address = "Bengaluru, Karnataka 560008, India";
            "address_id" = 29;
            "address_title" = "";
            "building_name" = "";
            latitude = "23.95579108";
            longitude = "77.64169808";
            "user_id" = 13;
        },
                {
            address = "Bengaluru, Karnataka 560008, India";
            "address_id" = 31;
            "address_title" = "";
            "building_name" = "";
            latitude = "22.95578162";
            longitude = "77.64173089";
            "user_id" = 13;
        },
                {
            address = "Bengaluru, Karnataka 560008, India";
            "address_id" = 37;
            "address_title" = "";
            "building_name" = "";
            latitude = "22.95577373";
            longitude = "77.64173507";
            "user_id" = 13;
        },
                  {
            address = "256, Road Number 19, Wadla Village, Vadala, Mumbai, Maharashtra 400031, India";
            "address_id" = 49;
            "address_title" = dsa;
            "building_name" = das;
            latitude = "19.01761470";
            longitude = "72.85616440";
            "user_id" = 13;
        }
    );
}

NSArray *resultArray = [[dict objectForKey:@"Address" allValues] filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(key == %@)", @"address"]];

NSMutableArray *resultArray = [NSMutableArray new];   
NSError *jsonError = [[NSError alloc] init];
NSDictionary *pR = [NSJSONSerialization JSONObjectWithData:yourJsonObject options:NSJSONReadingAllowFragments error:&jsonError];
NSArray *pArray = pR[@"Address"];

for(NSDictionary *dict in pR)
{
    [resultArray addObject:dict[@"address"]];
}