Ios 分析查询-无法处理多个whereKey:doesNotMatchKey:inQuery

我在试这个

PFQuery *allDealsQuery = [Deal query];
PFRelation *favoritedDealsRelation = [user objectForKey:@"favoritedDeals"];
PFQuery *favoritedDealsQuery = [favoritedDealsRelation query];

PFRelation *redeemedDealsRelation = [user objectForKey:@"redeemedDeals"];
PFQuery *redeemedDealsQuery = [redeemedDealsRelation query];

[allDealsQuery whereKey:@"objectId" doesNotMatchKey:@"objectId" inQuery:favoritedDealsQuery];
//Parse does not support more than 2 where queries???
[allDealsQuery whereKey:@"objectId" doesNotMatchKey:@"objectId" inQuery:redeemedDealsQuery];

    [allDealsQuery findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
        if (!error) {
            onSuccess(objects);
        }
        else {
            onError(error);
        }
    }];

当我尝试使用两个查询时，答案与预期的不同。

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那么，我是否应该只使用一个DoesNotMachKey查询？

尝试在复合查询上引用解析文档：

复合查询 如果要查找与多个查询之一匹配的对象，可以使用orQueryWithSubqueries:method。例如，如果你想找到赢得很多或很少的玩家，你可以：

PFQuery *lotsOfWins = [PFQuery queryWithClassName:@"Player"];
[lotsOfWins whereKey:@"wins" greaterThan:@150];

PFQuery *fewWins = [PFQuery queryWithClassName:@"Player"];
[fewWins whereKey:@"wins" lessThan:@5];
PFQuery *query = [PFQuery orQueryWithSubqueries:@[fewWins,lotsOfWins]];
[query findObjectsInBackgroundWithBlock:^(NSArray *results, NSError *error) {
  // results contains players with lots of wins or only a few wins.
}];