Ios 将用户定义的对象添加到NSMutableArray

我有下面的swift类，希望将其添加到NSMutableArray中

   class DrawerItem : NSObject{

    var tag : String = ""
    var title : String = ""

    override init () {

        self.tag = "";
        self.title = "";
    }

    init(tag: String) {

        self.tag = tag
    }

    init(title: String) {

        self.title = title
    }
}



self.dataSource = [NSMutableArray new];
[self.dataSource addObject:@"hello"]; //it works 

DrawerItem *item = [DrawerItem new]; // not working
item.tag = @"test";
item.title = @"test";

[self.dataSource addObject:item];

给我以下的例外

uncaught exception 'NSInvalidArgumentException', reason: '-[Khawater.DrawerItem isEqualToString:]: unrecognized selector sent to instance 

你可以这样做

    import Foundation

    class DrawerItem : NSObject{

        var tag : String = ""
        var title : String = ""

        override init () {

            self.tag = "";
            self.title = "";
        }

        init(tag: String) {

            self.tag = tag
        }

        init(title: String) {

            self.title = title
        }
    }

    //creating the first obj
    var drawer: DrawerItem = DrawerItem()

    drawer.tag = "Tag Test"
    drawer.title = "Title Test"

    //creating the second obj
    var drawer1: DrawerItem = DrawerItem()

    drawer1.tag = "Tag Test 1"
    drawer1.title = "Title Test 1"

    var drawerArray:[DrawerItem] = [DrawerItem]()

    //adding to the drawerArray
    drawerArray.append(drawer)
    drawerArray.append(drawer1)


    //testing the array
    for x in drawerArray{
        print(x.title)
    }

---

我认为这里的问题是在数据源数组中混合了

NSString

和

DrawerItem

。在以后的代码中，您尝试将其项仅用作字符串，这会引发运行时错误

解决方案编号1 在swift

var dataSource:[DrawerItem]=[]

中声明数组这将引发编译错误

第2号解决方案

---

使用objective-c轻量级泛型

@property（非原子，强）NSMutableArray*数据源如果存在不匹配，将生成编译器警告
您在此处混合了Objective-C和Swift。您是否在Objective-C类中使用Swift类？是的，我没有编译错误，异常发生在运行应用程序之后。您需要发布实际导致异常的代码。