Ios Swift-下一行的属性字符串背景色

我有一个标签，我希望在第1行显示一些单词，在第2行显示一些单词。我可以通过在字符串之间放置“\n”来实现它。第2行上的单词是带有背景色的属性字符串，但是背景色从第1行开始

有没有办法，我可以在第二行得到背景色

下面是代码：

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简单解决方案：-只需在一行字符串中添加/n即可解决问题

let attributedString = NSMutableAttributedString(string: "Line 1 Text\n" ?? "")
let attributesForNonSelectedRow = [NSAttributedString.Key.font:UIFont.systemFont(ofSize: 14, weight: UIFont.Weight.semibold),NSAttributedString.Key.foregroundColor:UIColor(rgb: 0x707070),NSAttributedString.Key.backgroundColor:UIColor(rgb: 0xE5E5E5)]
let myTitle = NSAttributedString(string: "Line 2 Text", attributes: attributesForNonSelectedRow)
attributedString.append(myTitle)
searchTitleLabel.lineBreakMode = .byWordWrapping
searchTitleLabel.numberOfLines = 0
searchTitleLabel.attributedText = attributedString

通过约束解决方案：

为什么不尝试通过提供前导、顶部和高度约束来设置标签的约束，就可以实现

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我写了这个问题。我所要做的就是将“\n”放在第1行的后面，而不是第2行的前面，这样就解决了背景色问题

let attributedString = NSMutableAttributedString(string: "Line 1 Text \n" ?? "")
let attributesForNonSelectedRow = [NSAttributedString.Key.font:UIFont.systemFont(ofSize: 14, weight: UIFont.Weight.semibold),NSAttributedString.Key.foregroundColor:UIColor(rgb: 0x707070),NSAttributedString.Key.backgroundColor:UIColor(rgb: 0xE5E5E5)]
let myTitle = NSAttributedString(string: "Line 2 Text", attributes: attributesForNonSelectedRow)
attributedString.append(myTitle)
searchTitleLabel.lineBreakMode = .byWordWrapping
searchTitleLabel.numberOfLines = 0
searchTitleLabel.attributedText = attributedString

let attributedString = NSMutableAttributedString(string: "Line 1 Text \n" ?? "")
let attributesForNonSelectedRow = [NSAttributedString.Key.font:UIFont.systemFont(ofSize: 14, weight: UIFont.Weight.semibold),NSAttributedString.Key.foregroundColor:UIColor(rgb: 0x707070),NSAttributedString.Key.backgroundColor:UIColor(rgb: 0xE5E5E5)]
let myTitle = NSAttributedString(string: "Line 2 Text", attributes: attributesForNonSelectedRow)
attributedString.append(myTitle)
searchTitleLabel.lineBreakMode = .byWordWrapping
searchTitleLabel.numberOfLines = 0
searchTitleLabel.attributedText = attributedString