检测iphone 6和6+；在模拟器ios中

我使用的是xcode 6，我为iPhone3.5（iphone4,4s）、4.0（iphone5,5s）、4.7（iphone6）和5.5（iphone6+）创建了不同的xib。 我正在使用此代码调用xib。这将在头文件中定义

#define IS_IPHONE_5 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )
#define IS_IPHONE_6 (fabs((double)[[UIScreen mainScreen]bounds].size.height - (double)667) < DBL_EPSILON)
#define IS_IPHONE_6_PLUS (fabs((double)[[UIScreen mainScreen]bounds].size.height - (double)736) < DBL_EPSILON)

但问题是，当我在iphone6和6+上运行这个应用程序时，它总是给出iphone5的结果。不要调用iphone6和6+xib。

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请帮助我。我尝试了所有与检测iphone6和6+相关的stackoverflow问题，但没有找到解决方案。

感谢您的回复，但对于iPhone5，它工作得很好，但在iphone6和6+中无法工作。您有iphone6和6+的启动映像吗？现在您将启动映像添加到项目中。通过此链接。。

- (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil
{
if (IS_IPHONE_5)
{
    UIScreen *mainScreen = [UIScreen mainScreen];
    NSLog(@"Screen bounds: %@, Screen resolution: %@, scale: %f, nativeScale: %f",NSStringFromCGRect(mainScreen.bounds), mainScreen.coordinateSpace, mainScreen.scale, mainScreen.nativeScale);
    self = [super initWithNibName:@"ViewController_Iphone5" bundle:nil];
}
if (IS_IPHONE_6) {
    self = [super initWithNibName:@"ViewController_iphone6" bundle:nil];

}
if (IS_IPHONE_6_PLUS) {
    UIScreen *mainScreen = [UIScreen mainScreen];
    NSLog(@"Screen bounds: %@, Screen resolution: %@, scale: %f, nativeScale: %f",NSStringFromCGRect(mainScreen.bounds), mainScreen.coordinateSpace, mainScreen.scale, mainScreen.nativeScale);
    self = [super initWithNibName:@"ViewController_iphone6+" bundle:nil];
}
else
{
    //iphone 3.5 inch
    UIScreen *mainScreen = [UIScreen mainScreen];
    NSLog(@"Screen bounds: %@, Screen resolution: %@, scale: %f, nativeScale: %f",NSStringFromCGRect(mainScreen.bounds), mainScreen.coordinateSpace, mainScreen.scale, mainScreen.nativeScale);
    self = [super initWithNibName:@"ViewController" bundle:nil];
}

return self;
}