Ios 无法将选定值从UIPickerView保存到数组
到目前为止,我已经尝试使用Ios 无法将选定值从UIPickerView保存到数组,ios,arrays,swift,xcode,uipickerview,Ios,Arrays,Swift,Xcode,Uipickerview,到目前为止,我已经尝试使用 func pickerView1(_ helpTypePicker: UIPickerView, didSelectRow row: Int, inComponent component: Int { infoListInit.requestInfoList[4] = (helpTypePickerValues[row]) } 但是该值并没有保存到数组中。保存后,我尝试打印该值,但没有效果。我的viewDidLoad func中确实有helpTypePick
func pickerView1(_ helpTypePicker: UIPickerView, didSelectRow row: Int, inComponent component: Int {
infoListInit.requestInfoList[4] = (helpTypePickerValues[row])
}
但是该值并没有保存到数组中。保存后,我尝试打印该值,但没有效果。我的viewDidLoad func中确实有helpTypePicker作为自委托,所以我不知道从这里可以走到哪里。UITextFields中的其他文本值保存得很好,但我的UIPickerViews中没有一个在这方面起作用
下面是完整的课程:
import Foundation
import UIKit
class requestHelpTypePickerScreen: UIViewController,
UIPickerViewDataSource, UIPickerViewDelegate {
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 1
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent
component: Int) -> Int {
if pickerView.tag == 1 {
return helpTypePickerValues.count
} else {
return languagePickerValues.count
}
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
if pickerView.tag == 1 {
return "\(helpTypePickerValues[row])"
} else {
return "\(languagePickerValues[row])"
}
}
// Mark: outlets
@IBOutlet weak var helpTypePicker: UIPickerView!
@IBOutlet weak var languagePicker: UIPickerView!
@IBOutlet weak var helpTypePickerLabel: UILabel!
let helpTypePickerValues = ["Academic/Professional", "Donate", "Food/Groceries", "Medication", "Emotional Support", "Misc."]
let languagePickerValues = ["Arabic", "Chinese", "Spanish", "English", "French", "Hindi/Urdu", "Korean", "Russian"]
override func viewDidLoad() {
super.viewDidLoad()
helpTypePicker.delegate = self
languagePicker.delegate = self
self.helpTypePicker.selectRow(2, inComponent: 0, animated: true)
self.languagePicker.selectRow(3, inComponent: 0, animated: true)
}
// Mark: actions
@IBAction func buttonPressed(_ sender: Any) {
func pickerView(_ helpTypePicker: UIPickerView,
didSelectRow row: Int,
inComponent component: Int) {
infoListInit.requestInfoList[5] = (helpTypePickerValues[row])
}
// this is called pickerView1 because it would conflict with the above
// function if called pickerView
func pickerView1(_ languagePicker: UIPickerView,
didSelectRow row1: Int,
inComponent component: Int) {
infoListInit.requestInfoList[6] = (languagePickerValues[row1])
}
performSegue(withIdentifier: "pickersDone", sender: nil)
}
代码中有一个错误,委托表示当在
UIPickerView
中选择新行时,将调用函数pickerView(uu2;:didSelectRow:incomonent:)
(参数名称无关紧要)
在您的示例中,当任何选择器选择新行时,pickerView(uux0:didSelectRow:incomonent:)
将被调用,并将选择器作为参数传递到第一个位置。您应该检查修改了哪个选择器,然后更改逻辑
就你而言:
func pickerView(pickerView:UIPickerView,didSelectRow行:Int,不完整组件:Int){
如果pickerView==helpTypePicker{
infoListInit.requestInfoList[5]=helpTypePickerValues[row]
}否则{
infoListInit.requestInfoList[6]=languagePickerValues[row]
}
}
函数本身是否被调用?或者它只是没有保存到数组中?函数名中似乎有输入错误,它说的是pickerView1
,而不是pickerView
(不带1)。请检查是否分配了委托。把相关的代码放进去理解