sendAsynchronousRequest在iOS 9中被弃用，如何修复我的函数

my

UIImageView

上的扩展正在向我发出警告。我想一个警告免费的项目，但我不知道如何妥善解决这个问题。我收到的警告是：

extension UIImageView {
    public func imageFromUrl(urlString: String) {
        if let url = NSURL(string: urlString) {
            let request = NSURLRequest(URL: url)
            NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()) {
                (response: NSURLResponse?, data: NSData?, error: NSError?) -> Void in
                if let imageData = data as NSData? {
                    self.image = UIImage(data: imageData)
                }
            }
        }
    }
}

sendAsynchronousRequest在iOS 9.0中被去除：使用[NSURLSession] dataTAskWithRequest

导致警告的扩展是：

extension UIImageView {
    public func imageFromUrl(urlString: String) {
        if let url = NSURL(string: urlString) {
            let request = NSURLRequest(URL: url)
            NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()) {
                (response: NSURLResponse?, data: NSData?, error: NSError?) -> Void in
                if let imageData = data as NSData? {
                    self.image = UIImage(data: imageData)
                }
            }
        }
    }
}

试试这个

Swift 3.0

URLSession.shared.dataTask(with: request) {data, response, error in
   if (error == nil) {
      //Do needful things // Your code . . . 
   } else {
      print("Error : \(error?.localizedDescription)");
   }
}.resume();

---

您的警告清楚地表明，

sendAsynchronousRequest在iOS 9.0中被删除：使用[nsurSession dataTAskWithRequest

，这意味着您应该使用

nsurSession

，而不是

NSURLConnection

你应该这样做

 var task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
    print("Response: \(response)")})

task.resume()

---

对于Swift 4.0使用以下选项：

let request = URLRequest(url: URL(string: "URL Here")!)

let session = URLSession.shared
let task = session.dataTask(with: request, completionHandler: { data, response, error -> Void in

    do {
        //your code here
    } catch {
        print("error")
    }

})

task.resume()