Ios 如何在Swift 4中编写JSON的可解码代码，其中键是动态的？

我有一个类似这样的JSON

我需要使用Swift 4在我的iOS应用程序中创建相应的可解码结构

{
    "cherry": {
        "filling": "cherries and love",
        "goodWithIceCream": true,
        "madeBy": "my grandmother"
     },
     "odd": {
         "filling": "rocks, I think?",
         "goodWithIceCream": false,
         "madeBy": "a child, maybe?"
     },
     "super-chocolate": {
         "flavor": "german chocolate with chocolate shavings",
         "forABirthday": false,
         "madeBy": "the charming bakery up the street"
     }
}

---

需要有关制作可解码结构的帮助。如何提及未知键，如

cherry

、

odd

和

super chocolate

您需要的是在定义

编码键时获得创造性。让我们将响应称为
FoodList
和内部结构
FoodDetail
。您尚未定义
FoodDetail
的属性，因此我假设所有键都是可选的

struct FoodDetail: Decodable {
    var name: String!
    var filling: String?
    var goodWithIceCream: Bool?
    var madeBy: String?
    var flavor: String?
    var forABirthday: Bool?

    enum CodingKeys: String, CodingKey {
        case filling, goodWithIceCream, madeBy, flavor, forABirthday
    }
}

struct FoodList: Decodable {
    var foodNames: [String]
    var foodDetails: [FoodDetail]

    // This is a dummy struct as we only use it to satisfy the container(keyedBy: ) function
    private struct CodingKeys: CodingKey {
        var intValue: Int?
        var stringValue: String

        init?(intValue: Int) { self.intValue = intValue; self.stringValue = "" }
        init?(stringValue: String) { self.stringValue = stringValue }
    }

    init(from decoder: Decoder) throws {
        self.foodNames = [String]()
        self.foodDetails = [FoodDetail]()

        let container = try decoder.container(keyedBy: CodingKeys.self)
        for key in container.allKeys {
            let foodName = key.stringValue
            var foodDetail = try container.decode(FoodDetail.self, forKey: key)
            foodDetail.name = foodName

            self.foodNames.append(foodName)
            self.foodDetails.append(foodDetail)
        }
    }
}


// Usage
let list = try! JSONDecoder().decode(FoodList.self, from: jsonData)

您希望在结构中如何准确地表示
cherry
、
odd
或
super chocolate
？您必须基本上使用Swift JSON API吗？还是您也愿意使用类似JSONModel的东西？@AndréSlotta我需要这些标题（cherry，odd，super chocolate）在数组中。@prabodhprakash我应该使用Swift的JSON API。没有本机方法可以做到这一点。库可以帮助你做到这一点。你能告诉我如何用这种方法实现可编码协议吗？不过，我找到了一个网站，解释了json解码和编码的所有内容。但是如何/在何处将foodName与FoodDetail对象关联？@vikzilla问得好。OP不清楚应该如何定义
FoodDetail
，所以我错过了名字。见编辑后的答案