Ios 通过参数从JSON获取数据集

尝试使用my参数从JSON中查找唯一的数据集

我有JSON“userDetails”：

}

我知道我的用户是Keila Maney（我的代码中有users属性），需要将该参数发送到JSON，然后只接收Keila Maney属性（它是imageUrl，content（type，url）），然后解析它们

在JSON中有没有标准的搜索方法

提前谢谢

Json示例：

{  
  "places": [  
    {  
      "name": "Ulrikh",
      "id": 555,
    },  
    {  
      "name": "Place 2",  
      "id": 1,  
    }
]  
} 

电话：

Swift方法：

func getDataByID(id : Int) {
        let data = self.getData()
        
        
            for i in 0..<data.count
            {
            if(Int((((data as NSDictionary)["places"] as! NSArray)[i] as! NSDictionary)["id"] as! Int) == id)
            {
                print("here is result:")
                print((((data as NSDictionary)["places"] as! NSArray)[i]))
            }
        }
    }
    
    func getData() -> NSDictionary {
        do{
            let path = Bundle.main.path(forResource: "test", ofType: "json")
            let jsonData = NSData(contentsOfFile: path!)
            let jsonResult:NSDictionary!  = try JSONSerialization.jsonObject(with: jsonData! as Data , options: JSONSerialization.ReadingOptions.mutableContainers) as! NSDictionary
            return jsonResult
        } catch let error as NSError {
            print(error)
        }
        
        return NSDictionary()
    }

func getDataByID（id:Int）{
让data=self.getData（）
对于0..NSDictionary中的i{
做{
让path=Bundle.main.path（forResource:“test”，类型为：“json”）
让jsonData=NSData（contentsOfFile:path！）
让jsonResult:NSDictionary！=尝试将JSONSerialization.jsonObject（使用：jsonData！作为数据，选项：JSONSerialization.ReadingOptions.mutableContainers）作为！NSDictionary
返回jsonResult
}将let错误捕获为NSError{
打印（错误）
}
返回NSDictionary（）
}

---

不感谢：）

只需创建UserDetails对象，如：

var userData:[UserDetails]？

并在循环中检查此项

userData[x]。name==“Keila Maney”

。然后此x将是Keila Maney的索引，您可以获取其所有数据。将json数据绑定到UserModel对象后。这是您将从json创建的三个类

用户模型

struct UserModel : Codable {
let userDetails : [UserDetails]?

enum CodingKeys: String, CodingKey {

     case userDetails = "userDetails"
}

init(from decoder: Decoder) throws {
   let values = try decoder.container(keyedBy: CodingKeys.self)
   userDetails = try values.decodeIfPresent([UserDetails].self, forKey:.userDetails)
}

}

用户详细信息

struct UserDetails : Codable {
let name : String?
let imageUrl : String?
let content : [Content]?

enum CodingKeys: String, CodingKey {

    case name = "name"
    case imageUrl = "imageUrl"
    case content = "content"
}

init(from decoder: Decoder) throws {
    let values = try decoder.container(keyedBy: CodingKeys.self)
    name = try values.decodeIfPresent(String.self, forKey: .name)
    imageUrl = try values.decodeIfPresent(String.self, forKey: .imageUrl)
    content = try values.decodeIfPresent([Content].self, forKey: .content)
}

}

内容

struct Content : Codable {
let type : String?
let url : String?

enum CodingKeys: String, CodingKey {

    case type = "type"
    case url = "url"
}

init(from decoder: Decoder) throws {
    let values = try decoder.container(keyedBy: CodingKeys.self)
    type = try values.decodeIfPresent(String.self, forKey: .type)
    url = try values.decodeIfPresent(String.self, forKey: .url)
}

}

---

这意味着

需要将该参数发送到JSON

？没有标准。这取决于后端。这意味着在JSON中，我有很多记录，我需要用我的参数过滤掉它们（在我的例子中，参数是“name”=“Keila Maney”）

struct UserDetails : Codable {
let name : String?
let imageUrl : String?
let content : [Content]?

enum CodingKeys: String, CodingKey {

    case name = "name"
    case imageUrl = "imageUrl"
    case content = "content"
}

init(from decoder: Decoder) throws {
    let values = try decoder.container(keyedBy: CodingKeys.self)
    name = try values.decodeIfPresent(String.self, forKey: .name)
    imageUrl = try values.decodeIfPresent(String.self, forKey: .imageUrl)
    content = try values.decodeIfPresent([Content].self, forKey: .content)
}

}

struct Content : Codable {
let type : String?
let url : String?

enum CodingKeys: String, CodingKey {

    case type = "type"
    case url = "url"
}

init(from decoder: Decoder) throws {
    let values = try decoder.container(keyedBy: CodingKeys.self)
    type = try values.decodeIfPresent(String.self, forKey: .type)
    url = try values.decodeIfPresent(String.self, forKey: .url)
}

}