Ios 如何在swift中从字符串数组中拆分字符串

我有一个

数组

像：

dateTime = ["2018/06/25 05:32:30","2018/05/25 02:37","2018/04/25 05:32:50","2018/07/25 06:30:30"]

需要拆分字符串并获得如下响应：

time = ["05:32:30","02:37","05:32:50","06:30:30"]

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任何人都可以在这方面提供帮助。

使用下面的解决方案从所有元素获取时间

let dateTime = ["2018/06/25 05:32:30","2018/05/25 02:37","2018/04/25 05:32:50","2018/07/25 06:30:30"]  
let array = dateTime.map { $0.components(separatedBy: " ")[1] }
 //["05:32:30", "02:37", "05:32:50", "06:30:30"]

---

您可以使用

flatMap

：

let dates = ["2018/06/25 05:32:30","2018/05/25 02:37","2018/04/25 05:32:50","2018/07/25 06:30:30"]
let times = dates.flatMap({ $0.split(separator: " ").last ?? nil })
print(times)
// prints: ["05:32:30", "02:37", "05:32:50", "06:30:30"]

---

循环每个项目并使用拆分函数

let times = dateTime.compactMap { $0.split(separator: " ").last }

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需要注意的是，如果未找到第二个元素，则使用下标

[1]

可能会导致空指针。这就是为什么

flatMap

更好的原因。请检查我的答案。你能告诉我为什么你把我的答案改成不被接受吗？