Ios coredatajson映射
在我的api中,我有一个类似这样的JSON输出Ios coredatajson映射,ios,json,core-data,mapping,Ios,Json,Core Data,Mapping,在我的api中,我有一个类似这样的JSON输出 { "restaurants": [{ "Restaurant": { "id": "3", "name": "...", "slug": "...", "phone": "2161234567", "address": "...", "city_id": "34", "county_id": "426", "di
{
"restaurants": [{
"Restaurant": {
"id": "3",
"name": "...",
"slug": "...",
"phone": "2161234567",
"address": "...",
"city_id": "34",
"county_id": "426",
"discount_type_id": null,
"discount": "",
"people_limit": "2",
"reservations_required": false,
"lat": "41.015608",
"lon": "28.934834",
"about": "...",
"logo": "...",
"logo_dir": "3",
"photo_1": "...",
"photo_2": null,
"photo_3": null,
"photo_dir": "3",
"created": "2012-11-30 16:30:21",
"modified": "2012-11-30 20:43:50",
"deleted": true
},
"AvailabilityRestriction": [{
"id": "1",
"title": "...",
"AvailabilityRestrictionRestaurant": {
"id": "28",
"restaurant_id": "3",
"availability_restriction_id": "1"
}
}],
"CuisineTag": [{
"id": "3",
"name": "...",
"CuisineTagRestaurant": {
"id": "47",
"restaurant_id": "3",
"cuisine_tag_id": "3"
}
}]
},
...
}
这家餐厅有很多美食标签和供应限制。还有一张城市表。。。同步它们的最佳方式是什么
我必须首先同步城市、美食标签和供应限制,然后在创建餐厅时,我将匹配它们?这条路对吗
谢谢。我会这样做 您应该在餐厅对象中拥有所有“餐厅”属性(即休息、烹饪标签) 下面是一个例子:
{
"Restaurants" : [
{
"id" : "3",
"name" : "...",
"slug" : "...",
"phone" : "2161234567",
"address" : "...",
"city_id" : "34",
"county_id" : "426",
"discount_type_id" : null,
"discount" : "",
"people_limit" : "2",
"reservations_required" : false,
"lat" : "41.015608",
"lon" : "28.934834",
"about" : "...",
"logo" : "...",
"logo_dir" : "3",
"photo_1" : "...",
"photo_2" : null,
"photo_3" : null,
"photo_dir" : "3",
"created" : "2012-11-30 16:30:21",
"modified" : "2012-11-30 20:43:50",
"deleted" : true,
"AvailabilityRestrictions" : [
{
"id" : "1",
"title" : "..."
},
{
"id" : "2",
"title" : "..."
}
],
"CuisineTags" : [
{
"id" : "3",
"name" : "..."
}
]
}
]
}
也要去掉“餐馆”的对象,这是不必要的。如果我有一个叫做餐馆的数组。我只想把餐馆放进去/从里面拿出来
我想你的问题还有很多,但我很难理解你需要什么。您是否在谈论如何在核心数据中建立它们之间的关系
如果您希望在cruisine标记和cities或其他我认为最好的方法之间设置关系,因为您可以循环JSON响应,如果其中一个属性是列表,则可以确定列表并获取正确的托管对象并创建关系
不过,为了清楚起见,您应该将这些城市、预定义的邮轮标签保留在不同的请求中。您希望API保持简单和灵活。是的,现在我正尝试像这样重新格式化JSON。CoreData会自动将字段与此格式匹配吗?那么“城市”表呢?如何匹配城市id?首先阅读以下内容:并充分理解它。您不希望API的更改破坏应用程序。如果您对核心数据不熟悉,还应该查看
Magical Record
,阅读本文以了解如何正确执行线程,谢谢。还有一个问题是;创建新的coredata对象(我已同步Cities实体)时,如何将city与Cities managedobject进行匹配?我将添加一个唯一的id,您可以使用该id获取city managed对象并设置餐厅与城市的关系。使用神奇的记录抓取方法非常简单:[City findFirstByAttribute:@“uid”With value:idOfCity]代码>