Ios 如何向NSDictionary中添加与键相关的对象

我有一个NSDictionary，现在我正试图在一个特定的键中添加一个对象。我该怎么做？下面是我的代码

let businessPhoneDic = ["locationname" : "",
                                "area" : "",
                              "number" : "",
                                "type" : "",
                       ];
let emailDic:NSMutableDictionary? = ["email" : "",];

let businessPhoneDic2 = ["locationname" : "hello",
                                 "area" : "",
                          "phonenumber" : "",
                                 "type" : "",
                        ];

var mainDictionary = ["businessPhone" : businessPhoneDic as AnyObject,"email" : emailDic as AnyObject,
        ];

现在我想将“businessPhoneDic2”添加到主词典中的键“businessPhone”。如何将其添加到Swift 3中

 mainDictionary["your key"] = businessPhoneDic2 as AnyObject // cast as per suggestions

---

根据定义，不能将两个值映射到同一个键。以下代码将替换旧钥匙：

Swift 3

mainDictionary["businessPhone"] = businessPhoneDic2

如果您的字典中需要两个值，只需使用一个新键，或者可以将字典数组存储为如下值：

var mainDictionary : [String : [NSDictionary]] = ["businessPhone" : [businessPhoneDic]]

然后：

---

首先，不要在Swift中使用

MSMutable…

集合类型。

使用本地Swift字典

let emailDic = ["email" : ""]

var dict = ["name": "Foo", "surname": "Bar"]

第二，用不同类型的字典注释为

[String:Any]

var mainDictionary : [String:Any] = ["businessPhone" : businessPhoneDic, "email" : emailDic]

---

如果键

businessPhone

的值是一个数组，则可以附加该值。如果是单个字典，则必须创建一个数组

本准则考虑了两种情况：

let businessPhone = mainDictionary["businessPhone"]

if var phone = businessPhone as? [[String:Any]] {
    phone.append(businessPhoneDic2)
    mainDictionary["businessPhone"] = phone
} else if let phone = businessPhone as? [String:Any] {
    mainDictionary["businessPhone"] = [phone, businessPhoneDic2]
}

---

Swift 3.x

//初始化字典

let emailDic = ["email" : ""]

var dict = ["name": "Foo", "surname": "Bar"]

//添加具有值的新键

dict["email"] = "foo.bar@email.com"
print(dict)

---

mainDictionary[“businessPhone”]=businessPhoneDic2是的，我正在尝试，但它只是用新值替换旧字典，所以当我用businessPhoneDic2更新它的replace businessPhoneDic后打印mainDictionary[“businessPhone”]时。是的，因为字典包含唯一键，并且只有一个对应于该键的值。因此，您不能为单个键存储多个值。是的，我想在前面的词典中为添加另一个值businessPhoneDic2和businessPhoneDic2包含相同的键值对。同样的逻辑，只允许唯一的键值对。为什么要进行向下投票？是的，我尝试过，但它只是用新值替换旧字典，所以当我打印mainDictionary[“businessPhone”]将其替换为businessPhoneDic2后，请使用不同的键，因为businessPhone键已存在。因此，如何合并两个字典并更新该特定键的字典？是否要将现有字典与新字典合并？我使用以下代码var mainDictionary:[字符串：[NSDictionary]]=[“businessPhone”：[businessPhoneDic作为NSDictionary]]mainDictionary[“businessPhone”]？.append（businessPhoneDic2作为NSDictionary）打印（===”，mainDictionary[“businessName”]作为AnyObject），但它当然会返回。您的mainDictionary中没有关键字businessName的值。您应该调用mainDictionary[businessPhone]。首先[“businessName”]就算businessPhoneDic字典有businessName键哦，很抱歉。是的，现在很好。我只想要一个，谢谢