iOS 9中的CLPlacemark到字符串

我想将

CLPlacemark

格式化为字符串

众所周知的方法是使用

ABCreateStringWithAddressDictionary

，但它在iOS 9中被弃用。警告告诉我改用

CNPostalAddressFormatter

但是，

CNPostalAddressFormatter

只能格式化

CNPostalAddress

。无法将

CLPlacemark

正确转换为

CNPostalAddress

；只有这三个属性由

CLPlacemark

和

CNPostalAddress

共享：

国家/地区

、

等国家/地区代码

和

邮政编码

---

那么，我现在应该如何将

CLPlacemark

格式化为字符串呢？

获取placemark的

addressDictionary

，并使用其

“FormattedAddressLines”

键提取地址字符串。请注意，这是字符串行的数组

（不过，你是对的，负责转换到Contacts框架的苹果开发者似乎完全忘记了通讯录和CLPlacemark之间的交换。这是Contacts框架中的一个严重缺陷，是众多缺陷之一。）

---

编辑因为我最初发布了这个答案，苹果修复了这个错误。CLPlacemark现在有一个

postalAddress

属性，它是一个CNPostalAddress，然后您可以使用CNPostalAddressFormatter来获得一个漂亮的多行地址字符串。确保导入联系人

Swift 4.1（和3&4，保存1行） 我阅读该问题是为了问“我该如何实施？” 两种方法 和其他海报一样，我首先选择移植AddressDictionary方法。但这意味着将失去

CNPostalAddress

类和格式化程序的功能和灵活性。因此，方法2

extension String {
    // original method (edited)
    init?(depreciated placemark1: CLPlacemark?) {
    // UPDATE: **addressDictionary depreciated in iOS 11**
        guard
            let myAddressDictionary = placemark1?.addressDictionary,
            let myAddressLines = myAddressDictionary["FormattedAddressLines"] as? [String]
    else { return nil }

        self.init(myAddressLines.joined(separator: " "))
}

    // my preferred method - let CNPostalAddressFormatter do the heavy lifting
    init?(betterMethod placemark2: CLPlacemark?) {
        // where the magic is:
        guard let postalAddress = CNMutablePostalAddress(placemark: placemark2) else { return nil }
        self.init(CNPostalAddressFormatter().string(from: postalAddress))
    }
}

等等，那是什么→ <代码>CNPostalAddress初始值设定项

extension CNMutablePostalAddress {
    convenience init(placemark: CLPlacemark) {
        self.init()
        street = [placemark.subThoroughfare, placemark.thoroughfare]
            .compactMap { $0 }           // remove nils, so that...
            .joined(separator: " ")      // ...only if both != nil, add a space.
    /*
    // Equivalent street assignment, w/o flatMap + joined:
        if let subThoroughfare = placemark.subThoroughfare,
            let thoroughfare = placemark.thoroughfare {
            street = "\(subThoroughfare) \(thoroughfare)"
        } else {
            street = (placemark.subThoroughfare ?? "") + (placemark.thoroughfare ?? "")
        } 
    */
        city = placemark.locality ?? ""
        state = placemark.administrativeArea ?? ""
        postalCode = placemark.postalCode ?? ""
        country = placemark.country ?? ""
        isoCountryCode = placemark.isoCountryCode ?? ""
        if #available(iOS 10.3, *) {
            subLocality = placemark.subLocality ?? ""
            subAdministrativeArea = placemark.subAdministrativeArea ?? ""
        }
    }
}

用法 在这里之前读书的人都会得到一件免费的T恤。（不太可能）

*该代码适用于Swift 3和4，但用于删除零值的

flatMap

已在Swift 4.1（文件，或参见以获取基本原理）中被折旧/重命名为

compactMap

。

Swift 3.0

---

Swift 3.0辅助方法

class func addressFromPlacemark(_ placemark:CLPlacemark)->String{
        var address = ""

        if let name = placemark.addressDictionary?["Name"] as? String {
            address = constructAddressString(address, newString: name)
        }

        if let city = placemark.addressDictionary?["City"] as? String {
            address = constructAddressString(address, newString: city)
        }

        if let state = placemark.addressDictionary?["State"] as? String {
            address = constructAddressString(address, newString: state)
        }

        if let country = placemark.country{
          address = constructAddressString(address, newString: country)
        }

        return address
      }

---

FormattedAddressLines按以下顺序返回数组：名称、街道、城市、州、邮政编码、国家。如果你打印placeString，你会看到类似这样的内容：“苹果公司，1无限循环，美国加利福尼亚州库珀蒂诺95014号”。你可以将你的代码显著提高1。在示例代码2中不使用其他库。使用

flatMap

+

joined

3。空合并，因为

CNPostalAddress

的所有成员都非空。附言：那么你就不必承诺免费t恤：P@Andy1]谢谢，隐藏分机已删除。2]

flatMap

+

已加入

。嗯，我会在评论中添加一个替代方案，告诉我你是否更喜欢它。3] 这是因为不能为它们分配

CLPlacemark

的字符串选项--CLPlacemark的属性需要合并，而不是

CNPostalAddress

，在iOS 11中，

CLPlacemark

有一个

CNPostalAddress

getter。读者注意：在给出正确答案的2年多时间里，

addressDictionary

已经贬值（在iOS 11中）。科技的巨轮在……上滚滚而来，

CLPlacemark

get

var postalAddress:CNPostalAddress？{get}

属性，锁定整个线程@AmitaiB是的，它现在纯粹是历史上的兴趣。。。！

func quickAndDirtyDemo() {
    let location = CLLocation(latitude: 38.8977, longitude: -77.0365)

    CLGeocoder().reverseGeocodeLocation(location) { (placemarks, _) in
        if let address = String(depreciated: placemarks?.first) {
            print("\nAddress Dictionary method:\n\(address)") }

        if let address = String(betterMethod: placemarks?.first) {
            print("\nEnumerated init method:\n\(address)") }
    }
}

/* Output:
Address Dictionary method:
The White House 1600 Pennsylvania Ave NW Washington, DC  20500 United States

Enumerated init method:
1600 Pennsylvania Ave NW
Washington DC 20500
United States
*/

if let lines = myCLPlacemark.addressDictionary?["FormattedAddressLines"] as? [String] {
    let placeString = lines.joined(separator: ", ")
    // Do your thing
}

class func addressFromPlacemark(_ placemark:CLPlacemark)->String{
        var address = ""

        if let name = placemark.addressDictionary?["Name"] as? String {
            address = constructAddressString(address, newString: name)
        }

        if let city = placemark.addressDictionary?["City"] as? String {
            address = constructAddressString(address, newString: city)
        }

        if let state = placemark.addressDictionary?["State"] as? String {
            address = constructAddressString(address, newString: state)
        }

        if let country = placemark.country{
          address = constructAddressString(address, newString: country)
        }

        return address
      }