Ios 维玛？isn'；无法转换为UIImage:Xcode在尝试使用原始映像时抛出错误

我正在尝试构建一个iOS应用程序，允许您从库中拾取图像，但它不断失败，错误为“UIImage”无法转换为UIImage。是否有办法修复此错误或从现在起绕过此错误？我正在MacOS 10.14上运行Xcode 10.1。

信息[.originalImage]是Any？值。它好像可以包含UIImage？值或nil。因此，请尝试：

 func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
    // The info dictionary may contain multiple representations of the image. You want to use the original.
    guard let selectedImage = info[.originalImage] as?
        UIImage else {
        fatalError("Expected a dictionary containing an image, but was provided the following: \(info)")
    }

    // Set photoImageView to display the selected image.
    photoImageView.image = selectedImage

    // Dismiss the picker.
    dismiss(animated: true, completion: nil)
}

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将该问号添加到UIImage。仅此而已。

将

.originalImage

替换为

UIImagePickerControllerOriginalImage

这对我有用。 Xcode版本：10.1

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Swift版本：4.0

使用正确的方法签名开始：

func imagePickerController（picker:UIImagePickerController，didFinishPickingMediaWithInfo:[UIImagePickerController.InfoKey:Any]）

。在您的guard语句中，我认为您不需要？在as.as@rmaddy已经在上面进行了注释之后，委托方法的签名是错误的。info参数的类型必须为“[UIImagePickerController.InfoKey:Any]”，请参阅

guard guard let selectedImage = info[.originalImage] as? UIImage?  else { ... }