如何使用objective C在ios 9中使用条件调用json

这是我的json web响应

-Itinerary: [
    -{
        ID: "1",
        ValueOne: "2473.05",
        ValueTwo: "368.95"

    },
    -{
        ID: "2",
        ValueOne: "2453.05",
        ValueTwo: "308.95"

    }
],
-Details :[
    -{
        ID:"1",
        FirstName:"Graham",
        LastName:"Json"
    },
    -{
        ID:"1",
        FirstName:"Anuradh",
        LastName:"Stackoverflow"
    }

]

什么应该是

响应

对象类型。我喜欢这样，它是正确的还是不重要的类型

NSDictionary *Results = (NSDictionary *)responseObject;

然后我得到了回复。现在我想得到的是

行程

详细信息和 仅当

行程ID

等于

详细信息ID

时，才能获取

详细信息。我如何才能做到这一点

   NSArray *Itinerary = [Resulsts objectForKey=@"Itinerary"];
    NSArray *Itinerary = [Resulsts objectForKey=@"Detailss"];

    for(NSDictionary *itinry in Itinerary)
    {
        NSString *Iid = [itinry objectForKey="ID"];
        NSString *ValOne = [itinry objectForKey="ValueOne"];
        //like this I'm getting values
        //then here I want to get all details which it's `itinerary` `ID` equal to `Details` `ID`.how can I do that.
    }

然后在这里我想得到所有的细节，它的
行程
ID
等于
细节
ID
。我该怎么做。
请尝试这个代码，希望它能为您工作

   NSArray *Itinerary = [Resulsts objectForKey=@"Itinerary"];
    NSArray *Itinerary = [Resulsts objectForKey=@"Detailss"];

    for(NSDictionary *itinry in Itinerary)
    {
        NSString *Iid = [itinry objectForKey="ID"];
        NSString *ValOne = [itinry objectForKey="ValueOne"];
        //like this I'm getting values
        //then here I want to get all details which it's `itinerary` `ID` equal to `Details` `ID`.how can I do that.
    }

  NSArray *Itinerary = [Resulsts objectForKey=@"Itinerary"];
    NSArray *dTinerary = [Resulsts objectForKey=@"Detailss"];

    for(int i=0; i<Itinerary;i++)
    {
        NSString *iID=[[Itinerary objectAtIndex:i] objectForKey:@"ID"];

        NSString *dID=[[dTinerary objectAtIndex:i] objectForKey:@"ID"];

        if ([iID isEqualToString:dID])
        {

            // do your thinks here

            NSLog(@"%@",[[Itinerary objectAtIndex:i] objectForKey:@"ValueOne"]);
               // break;
        }

//        NSString *Iid = [itinry objectForKey="ID"];
       // NSString *ValOne = [itinry objectForKey="ValueOne"];
        //like this I'm getting values
        //then here I want to get all details which it's `itinerary` `ID` equal to `Details` `ID`.how can I do that.
    }

NSArray*行程=[results objectForKey=@“行程”]；
NSArray*dtineary=[results objectForKey=@“Detailss”]；
对于（int i=0；i请尝试此代码，希望它对您有用

  NSArray *Itinerary = [Resulsts objectForKey=@"Itinerary"];
    NSArray *dTinerary = [Resulsts objectForKey=@"Detailss"];

    for(int i=0; i<Itinerary;i++)
    {
        NSString *iID=[[Itinerary objectAtIndex:i] objectForKey:@"ID"];

        NSString *dID=[[dTinerary objectAtIndex:i] objectForKey:@"ID"];

        if ([iID isEqualToString:dID])
        {

            // do your thinks here

            NSLog(@"%@",[[Itinerary objectAtIndex:i] objectForKey:@"ValueOne"]);
               // break;
        }

//        NSString *Iid = [itinry objectForKey="ID"];
       // NSString *ValOne = [itinry objectForKey="ValueOne"];
        //like this I'm getting values
        //then here I want to get all details which it's `itinerary` `ID` equal to `Details` `ID`.how can I do that.
    }

NSArray*行程=[results objectForKey=@“行程”]；
NSArray*dtineary=[results objectForKey=@“Detailss”]；
对于（int i=0；iYou有两个选项1.从JSON字符串中删除“-”，然后获取ID和详细信息。2.使用NSArray*行程=[Results objectForKey=@”-行程]；对于获取值，然后从所有值中删除“-”。您有两个选项1.从JSON字符串中删除“-”，然后获取ID和详细信息。2.使用NSArray*行程=[Results objectForKey]=@“-行程”]；用于获取值&稍后从所有值中删除“-”。如果两个ID相等，如何获取详细信息NSSTRING*getDetails=[[INVINERARY objectAtIndex:i]objectForKey:@“ValueOne”]当
行程
ID
=
1
和
详细信息
ID
=
1
此时，我想获取
详细信息
数组中的所有详细信息，其中的
ID
=
1
.NSString*getID=[[dtineral objectAtIndex:I]objectForKey:@“ID”]；NSString*获取FirstName=[[dtinerry objectAtIndex:i]objectForKey:@“FirstName”]；NSString*get LastName=[[dtinerry objectAtIndex:i]objectForKey:@“LastName”]；我投了赞成票，如果它对我有效，那么我将接受。thanx和good one如果两个ID相等，如何获取详细信息NSString*getDetails=[[行程对象atindex:i]objectForKey:@“ValueOne”]当
行程
ID
=
1
和
详细信息
ID
=
1
此时，我想获取
详细信息
数组中的所有详细信息，其中的
ID
=
1
.NSString*getID=[[dtineral objectAtIndex:I]objectForKey:@“ID”]；NSString*获取FirstName=[[dtineral objectAtIndex:i]objectForKey:@“FirstName”]；NSString*get LastName=[[dtineral objectAtIndex:i]objectForKey:@“LastName”]；我投了赞成票，如果它对我有效，我会接受。谢谢，很好