在Obj-C（iPad）中画一个形状，看我是否点击了它

我有两个视图，里面有一些形状奇怪的PNG。我想在每个uiview的顶部绘制一个不可见的形状，并检测我是否点击了这些形状。否则，通过重叠可以看到抽头。我以为我下面的代码会允许这种情况发生，但根本没有显示任何接触

-(void)drawRect:(CGRect)rect {
    quadrantOnePath = CGPathCreateMutable();
    CGPathMoveToPoint(quadrantOnePath, NULL, 30, 214);
    CGPathAddLineToPoint(quadrantOnePath, NULL, 281, 47);
    CGPathAddLineToPoint(quadrantOnePath, NULL, 493, 51);
    CGPathAddLineToPoint(quadrantOnePath, NULL, 306, 376);
    CGPathCloseSubpath(quadrantOnePath);
}

//in viewdidload

UITapGestureRecognizer *tapBlueRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(viewBlueFloorplans:)];
[tapBlueRecognizer setNumberOfTapsRequired:1];
[tapBlueRecognizer setDelegate:self];
[floorBlueHolderview addGestureRecognizer:tapBlueRecognizer];


// viewbluefunction
-(void)viewBlueFloorplans:(id)sender meso:(UIGestureRecognizer *)recognizer {

   CGPoint factor = [recognizer locationOfTouch:0 inView:self.view];
   bool processTouch = CGPathContainsPoint(quadrantOnePath, NULL, factor, true);

   if(processTouch) {
    NSLog(@"tap_viewBLU");
   }
}

---

1，实际上不必绘制形状，就可以在其上使用CGPathContainsPoint。如果您知道形状正确，请将

quadrantOnePath = CGPathCreateMutable();
CGPathMoveToPoint(quadrantOnePath, NULL, 30, 214);
CGPathAddLineToPoint(quadrantOnePath, NULL, 281, 47);
CGPathAddLineToPoint(quadrantOnePath, NULL, 493, 51);
CGPathAddLineToPoint(quadrantOnePath, NULL, 306, 376);
CGPathCloseSubpath(quadrantOnePath);

如果形状不变，则输入“viewdidload”。（为防止内存泄漏，请不要忘记释放quadrantOnePath） 如果不想调试形状，请绘制它

2、

@选择器（viewBlueFloorplans:）

将不会调用

-（void）viewBlueFloorplans:（id）发送方meso:（uigestureRecognitizer*）识别器

@选择器（viewBlueFloorplans:）

将调用

-（void）viewBlueFloorplans:（UIgestureRecognitor*）识别器

---

3，如果您实际上没有实现委托方法，那么

[TapblueRecognitor setDelegate:self]以节省一些计算。
是
floorBlueHolderView
不可见的形状吗？