Iphone 在iOS 7中访问AddressBook时出现各种内存泄漏

我正在使用此函数访问联系人列表，并使用MContact类保存联系人对象，但此代码给了我一些内存泄漏，我无法解决此问题。请帮助

 +(NSArray *)getAllContacts

{

    CFErrorRef *error = nil;


    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);

    __block BOOL accessGranted = NO;
    if (ABAddressBookRequestAccessWithCompletion != NULL) { // we're on iOS 6
        dispatch_semaphore_t sema = dispatch_semaphore_create(0);
        ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
            accessGranted = granted;
            dispatch_semaphore_signal(sema);
        });
        dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);

    }
    else { // we're on iOS 5 or older
        accessGranted = YES;
    }

    if (accessGranted) {

#ifdef DEBUG
        NSLog(@"Fetching contact info ----> ");
#endif


        ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
        ABRecordRef source = ABAddressBookCopyDefaultSource(addressBook);
        CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(addressBook, source, kABPersonSortByFirstName);
        CFIndex nPeople = ABAddressBookGetPersonCount(addressBook);
        NSMutableArray* items = [NSMutableArray arrayWithCapacity:nPeople];


        for (int i = 0; i < nPeople; i++)
        {
            MContact *contacts = [MContact new];

            ABRecordRef person = CFArrayGetValueAtIndex(allPeople, i);

            //get First Name and Last Name

            contacts.firstName = (__bridge NSString*)ABRecordCopyValue(person, kABPersonFirstNameProperty);

            contacts.lastName =  (__bridge NSString*)ABRecordCopyValue(person, kABPersonLastNameProperty);

            if (!contacts.firstName) {
                contacts.firstName = @"";
            }
            if (!contacts.lastName) {
                contacts.lastName = @"";
            }


            NSMutableArray *contactEmails = [NSMutableArray new];
            ABMultiValueRef multiEmails = ABRecordCopyValue(person, kABPersonEmailProperty);

            for (CFIndex i=0; i<ABMultiValueGetCount(multiEmails); i++) {
                CFStringRef contactEmailRef = ABMultiValueCopyValueAtIndex(multiEmails, i);
                NSString *contactEmail = (__bridge NSString *)contactEmailRef;

                [contactEmails addObject:contactEmail];
                // NSLog(@"All emails are:%@", contactEmails);

            }

            if([contactEmails count]==0){
                return items ;
            }
            else{
                [contacts setemails:contactEmails];
                [items addObject:contacts];

            }




#ifdef DEBUG
    #endif




        }
        CFRelease(addressBook);
        return items;



    } else {
#ifdef DEBUG
        NSLog(@"Cannot fetch Contacts :( ");        
#endif
        return NO;


    }


}

+（NSArray*）获取所有联系人
{
CFErrorRef*错误=nil；
ABAddressBookRef addressBook=ABAddressBookCreateWithOptions（空，错误）；
__block BOOL accessgrated=否；
如果（ABAddressBookRequestAccessWithCompletion！=NULL）{//我们在iOS 6上
dispatch\u semaphore\u t sema=dispatch\u semaphore\u create（0）；
ABAddressBookRequestAccessWithCompletion（addressBook，^（已授予bool，CFErrorRef错误）{
accessgrated=已授予；
调度信号量信号（sema）；
});
调度信号量等待（永远调度时间）；
}
否则{//我们使用的是iOS 5或更高版本
accessgrated=是；
}
如果（已授予访问权限）{
#ifdef调试
NSLog（@“获取联系信息---->”）；
#恩迪夫
ABAddressBookRef addressBook=ABAddressBookCreateWithOptions（空，错误）；
ABRecordRef source=ABAddressBookCopyDefaultSource（地址簿）；
CFArrayRef allPeople=abAddressBookCopyArrayFallPeopleInSourceWithSortOrdering（addressBook、source、kABPersonSortByFirstName）；
CFIndex nppeople=ABAddressBookGetPersonCount（地址簿）；
NSMutableArray*items=[NSMutableArray阵列容量：NPEOPE]；
for（int i=0；i对于（CFIndex i=0；i这里需要注意的是，按照惯例，“复制”的函数返回的对象引用计数增加，就像“创建”的函数一样。因此，按照您发布
通讯簿的方式，您也需要对复制的对象执行此操作。或者，当您将CFObjects桥接到NSObjects时，
\u桥接\u传输
会将所有权传递给ARC，以便ARC可以为您释放它

这里的另一个问题是函数中的多个返回点。如果这是您想要做的，您需要确保在每次
返回之前都清理了相应的内容

希望我已经抓住了这里的一切：

+ (NSArray *)getAllContacts
{
    CFErrorRef *error = nil;

    ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);

    __block BOOL accessGranted = NO;
    if (ABAddressBookRequestAccessWithCompletion != NULL) { // we're on iOS 6
        dispatch_semaphore_t sema = dispatch_semaphore_create(0);
        ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
            accessGranted = granted;
            dispatch_semaphore_signal(sema);
        });
        dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
    }
    else { // we're on iOS 5 or older
        accessGranted = YES;
    }

    if (accessGranted) {

#ifdef DEBUG
        NSLog(@"Fetching contact info ----> ");
#endif


        //ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error); Removing this line as you have this already. If you need to recreate, you must release the first one.
        ABRecordRef source = ABAddressBookCopyDefaultSource(addressBook);
        CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(addressBook, source, kABPersonSortByFirstName);
        CFRelease(source); // Copied object, so release.
        CFIndex nPeople = ABAddressBookGetPersonCount(addressBook);
        NSMutableArray* items = [NSMutableArray arrayWithCapacity:nPeople];

        for (int i = 0; i < nPeople; i++)
        {
            MContact *contacts = [MContact new];

            ABRecordRef person = CFArrayGetValueAtIndex(allPeople, i);

            //get First Name and Last Name

            contacts.firstName = (__bridge_transfer NSString*)ABRecordCopyValue(person, kABPersonFirstNameProperty);

            contacts.lastName =  (__bridge_transfer NSString*)ABRecordCopyValue(person, kABPersonLastNameProperty);

            if (!contacts.firstName) {
                contacts.firstName = @"";
            }
            if (!contacts.lastName) {
                contacts.lastName = @"";
            }

            NSMutableArray *contactEmails = [NSMutableArray new];
            ABMultiValueRef multiEmails = ABRecordCopyValue(person, kABPersonEmailProperty);

            for (CFIndex i=0; i<ABMultiValueGetCount(multiEmails); i++) {
                CFStringRef contactEmailRef = ABMultiValueCopyValueAtIndex(multiEmails, i);
                NSString *contactEmail = (__bridge_transfer NSString *)contactEmailRef;

                [contactEmails addObject:contactEmail];
                // NSLog(@"All emails are:%@", contactEmails);

            }
            CFRelease(multiEmails);                

            if([contactEmails count]==0) {
                break; 
                // If we return here, we'll leak addressBook and allPeople
                // We could release both, then return.
            }
            else {
                [contacts setemails:contactEmails];
                [items addObject:contacts];
            }


#ifdef DEBUG
    #endif

        }
        CFRelease(addressBook);
        CFRelease(allPeople); // Copied, so must release
        return items;



    } else {
#ifdef DEBUG
        NSLog(@"Cannot fetch Contacts :( ");        
#endif
        CFRelease(addressBook);
        return nil;


    }
}

+（NSArray*）获取所有联系人
{
CFErrorRef*错误=nil；
ABAddressBookRef addressBook=ABAddressBookCreateWithOptions（空，错误）；
__block BOOL accessgrated=否；
如果（ABAddressBookRequestAccessWithCompletion！=NULL）{//我们在iOS 6上
dispatch\u semaphore\u t sema=dispatch\u semaphore\u create（0）；
ABAddressBookRequestAccessWithCompletion（addressBook，^（已授予bool，CFErrorRef错误）{
accessgrated=已授予；
调度信号量信号（sema）；
});
调度信号量等待（永远调度时间）；
}
否则{//我们使用的是iOS 5或更高版本
accessgrated=是；
}
如果（已授予访问权限）{
#ifdef调试
NSLog（@“获取联系信息---->”）；
#恩迪夫
//ABAddressBookRef addressBook=ABAddressBookCreateWithOptions（NULL，错误）；删除此行，因为您已经有了这行。如果需要重新创建，必须释放第一行。
ABRecordRef source=ABAddressBookCopyDefaultSource（地址簿）；
CFArrayRef allPeople=abAddressBookCopyArrayFallPeopleInSourceWithSortOrdering（addressBook、source、kABPersonSortByFirstName）；
CFRelease（source）；//复制的对象，因此释放。
CFIndex nppeople=ABAddressBookGetPersonCount（地址簿）；
NSMutableArray*items=[NSMutableArray阵列容量：NPEOPE]；
for（int i=0；i对于（CFIndex i=0；iSorry，找到了一封我错过的邮件-
多封电子邮件
也需要发布。我在回答中编辑了代码。谢谢。这对我帮助很大。：）