Iphone 程序因API调用而崩溃

Iphone 程序因API调用而崩溃,iphone,json,api,Iphone,Json,Api,我有两页: 登录页面和注册页面: 对于登录页面,我使用以下方法获取信息并将失败或成功响应传递给用户: - (void)login:(UIButton *)sender { [self.appDel.api loginWithEmail:self.email.text password:self.password.text completionHandler:^(id response, NSErro

我有两页:

登录页面和注册页面:

对于登录页面,我使用以下方法获取信息并将失败或成功响应传递给用户:

- (void)login:(UIButton *)sender
{
    [self.appDel.api loginWithEmail:self.email.text
                           password:self.password.text
                  completionHandler:^(id response, NSError *error) {
                      if (error) {
                          NSLog(@"ERROR: %@", error);
                      } else {
                          if ([[response objectForKey:Status] isEqualToString:Success]) {
                              self.currentUser = [response objectForKey:kResponseUser];
                              self.currentUserProfile = [response objectForKey:Profile];
                              [self.presentingViewController dismissViewControllerAnimated:YES completion:NULL];
                          } else {
                              NSLog(@"FAIL: %@", response);
                              [[[UIAlertView alloc] initWithTitle:@"Login Failed"
                                                          message:[response description]
                                                         delegate:nil
                                                cancelButtonTitle:@"OK"
                                                otherButtonTitles:nil] show];
                          }
                      }
                  }];
}
使用此登录页面时,如果用户未填写两个必填字段,或者其中一个字段已填充,另一个字段为空,然后按login键,他将收到失败消息

然而,在注册案例中,当文本字段为空并且我们单击注册时,程序崩溃。我应该如何改变这一点:

-(void)signUp:(UIButton *)sender
{
    [self.api signup:self.Email.text
                                   password:self.Password.text
                       confirmationPassword:self.ConfirmPassword.text
                                  firstName:self.FirstName.text
                          completionHandler:^(id response, NSError *error) {
    if (error) {
        NSLog(@"ERROR: %@", error);
    } else {
        if ([[response objectForKey:Status] isEqualToString:Success]) {
        self.appDel.theNewUser = [response objectForKey:User];
        self.appDel.theNewUserProfile = [response objectForKey:Profile];
            [self.presentingViewController dismissViewControllerAnimated:YES completion:NULL];
        } else {
            NSLog(@"FAIL: %@", response);
            [[[UIAlertView alloc] initWithTitle:@"SignUp Failed"
                                        message:[response description]
                                       delegate:nil
                              cancelButtonTitle:@"OK"
                              otherButtonTitles:nil] show];
        }
    }
}];

}
在您的注册方法中(或者更好的是,在您的API类中),检测nil和空值。现在的问题是在字典中插入一个nil值

下面是一个使用您的代码的示例。我检查是否有任何值长度等于零,如果是,记录一点错误

-(void)signUp:(UIButton *)sender
{

    if ([[[self Email] text] length] == 0 ||
        [[[self Password] text] length] == 0 ||
        [[[self ConfirmPassword] text] length] == 0 ||
        [[[self FirstName] text] length] == 0) {

        // add an error alert here?

        NSLog(@"Hold on there!  You haven't filled everything in.");

        return;

    }

    [self.api signup:self.Email.text
                                   password:self.Password.text
                       confirmationPassword:self.ConfirmPassword.text
                                  firstName:self.FirstName.text
                          completionHandler:^(id response, NSError *error) {
    if (error) {
        NSLog(@"ERROR: %@", error);
    } else {
        if ([[response objectForKey:Status] isEqualToString:Success]) {
        self.appDel.theNewUser = [response objectForKey:User];
        self.appDel.theNewUserProfile = [response objectForKey:Profile];
            [self.presentingViewController dismissViewControllerAnimated:YES completion:NULL];
        } else {
            NSLog(@"FAIL: %@", response);
            [[[UIAlertView alloc] initWithTitle:@"SignUp Failed"
                                        message:[response description]
                                       delegate:nil
                              cancelButtonTitle:@"OK"
                              otherButtonTitles:nil] show];
        }
    }
}];

}

请告诉我们您正在接收的崩溃消息。由于未捕获的异常“NSInvalidArgumentException”而终止应用程序,原因:'***-[\u NSPlaceholderDictionary initWithObjects:forKeys:count::]:尝试从对象[0]插入nil对象'***第一次抛出调用堆栈:(0x15d2012 0x12dfe7e 0x1598a95 0x15c54e9 0xe116 0x7955 0x12f3705 0x22a920 0x22a8b8 0x2eb671 0x2EBCF 0x2ead38 0x25a33f 0x25a552 0x2383aa 0x229cf8 0x2634df9 0x2634ad0 0x1547bf5 0x1547962 0x1578bb6 0x1577F4 0x1577e1b 0x26337e3 0x2633668 0x22765c 0x297d 0x28A50x1)libc++abi.dylib:terminate调用抛出异常那么你认为定义新键(newuser,newuser profile)也是必需的,或者我可以使用我登录时使用的currentUser和currentUserProfile?好的,很酷。很容易修复(见下面的答案)。你能发布异常的堆栈跟踪吗?我不确定它是否发生在上面发布的代码中。谢谢,问题解决了,但是这个案例是如何处理的?我如何在屏幕上向用户显示消息?不确定为什么它不会在登录时为你崩溃,因为你没有发布这些方法。零值,比如什么是保护然而,这是您的问题。对于登录,它从json接收失败消息,如下所示:login Failed:reason=“error user/password”;status=fail;}