Iphone 将NSPredicate与嵌套数组一起使用

我有一个这样的数组

NSMutableArray *level1;
NSMutableArray *level2;
NSMutableArray *level3;

self.questionSections=[[NSArray alloc] initWithObjects:@"Level 1",@"Level 2",@"Level 3", nil];

level1=[[NSMutableArray alloc] init];
level2=[[NSMutableArray alloc] init];
level3=[[NSMutableArray alloc] init];

[level1 addObject:[[NSDictionary alloc] initWithObjectsAndKeys:
                   @"What is the opposite of up?",@"name",
                   @"101q.png",@"questionpicture",
                   nil]];

[level1 addObject:[[NSDictionary alloc] initWithObjectsAndKeys:
                   @"What is the opposite of front?",@"name",
                   @"102q.png",@"questionpicture",
                   nil]];


[level2 addObject:[[NSDictionary alloc] initWithObjectsAndKeys:
                   @"Name a common pet?",@"name",
                   @"201q.png",@"questionpicture",
                   nil]];


[level2 addObject:[[NSDictionary alloc] initWithObjectsAndKeys:
                   @"Name a common bird?",@"name",
                   @"202q.png",@"questionpicture",
                   nil]];


[level3 addObject:[[NSDictionary alloc] initWithObjectsAndKeys:
                   @"List 3 rooms in your house?",@"name",
                   @"301q.png",@"questionpicture",
                   nil]];

self.questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

我想搜索一下。我试过了，但一无所获

NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"name CONTAINS 'the'"];

NSLog(@"%@",resultPredicate);
NSLog(@"%@",self.questionData);

self.searchResults=[self.questionData  filteredArrayUsingPredicate:resultPredicate];

NSLog(@"%@",self.searchResults);

resultPredicate

外观良好“名称包含'the'”

self.questionData

看起来不错

但是

self.searchResults

只是（）

---

任何有帮助的想法都会很好。谢谢。

这里是阵列的问题

(
        (
                {
            name = "What is the opposite of up?";
            questionpicture = "101q.png";
        },
                {
            name = "What is the opposite of front?";
            questionpicture = "102q.png";
        }
    ),
        (
                {
            name = "Name a common pet?";
            questionpicture = "201q.png";
        },
                {
            name = "Name a common bird?";
            questionpicture = "202q.png";
        }
    ),
        (
                {
            name = "List 3 rooms in your house?";
            questionpicture = "301q.png";
        }
    )
)

为了处理上述谓词，数组必须如下所示

(
        {
        name = "What is the opposite of up?";
        questionpicture = "101q.png";
    },
        {
        name = "What is the opposite of front?";
        questionpicture = "102q.png";
    },
        {
        name = "Name a common pet?";
        questionpicture = "201q.png";
    },
        {
        name = "Name a common bird?";
        questionpicture = "202q.png";
    },
        {
        name = "List 3 rooms in your house?";
        questionpicture = "301q.png";
    }
)

 NSArray *questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"name CONTAINS 'the'"];


NSMutableArray *resultarray= [[NSMutableArray alloc]init];
for(int i=0;i<[questionData count];i++){
    NSArray* searchResults=[[questionData objectAtIndex:i]  filteredArrayUsingPredicate:resultPredicate];
    if([searchResults count]>0)
        [resultarray addObject:searchResults];
}
NSLog(@"%@",resultarray);
O/P:-
 (
        (
                {
            name = "What is the opposite of up?";
            questionpicture = "101q.png";
        },
                {
            name = "What is the opposite of front?";
            questionpicture = "102q.png";
        }
    )
)

编辑：-像这样尝试

(
        {
        name = "What is the opposite of up?";
        questionpicture = "101q.png";
    },
        {
        name = "What is the opposite of front?";
        questionpicture = "102q.png";
    },
        {
        name = "Name a common pet?";
        questionpicture = "201q.png";
    },
        {
        name = "Name a common bird?";
        questionpicture = "202q.png";
    },
        {
        name = "List 3 rooms in your house?";
        questionpicture = "301q.png";
    }
)

 NSArray *questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"name CONTAINS 'the'"];


NSMutableArray *resultarray= [[NSMutableArray alloc]init];
for(int i=0;i<[questionData count];i++){
    NSArray* searchResults=[[questionData objectAtIndex:i]  filteredArrayUsingPredicate:resultPredicate];
    if([searchResults count]>0)
        [resultarray addObject:searchResults];
}
NSLog(@"%@",resultarray);
O/P:-
 (
        (
                {
            name = "What is the opposite of up?";
            questionpicture = "101q.png";
        },
                {
            name = "What is the opposite of front?";
            questionpicture = "102q.png";
        }
    )
)

NSArray*questionData=[[NSArray alloc]initWithObjects:level1、level2、level3、nil]；
NSPredicate*resultPredicate=[NSPredicate predicateWithFormat:@“名称包含‘the’”）；
NSMutableArray*resultarray=[[NSMutableArray alloc]init]；
对于（int i=0；i0）
[resultarray addObject:searchResults]；
}
NSLog（@“%@”，结果数组）；
O/P:-
(
(
{
name=“up的反面是什么？”；
questionpicture=“101q.png”；
},
{
name=“前面的反面是什么？”；
questionpicture=“102q.png”；
}
)
)

这里是数组的问题

(
        (
                {
            name = "What is the opposite of up?";
            questionpicture = "101q.png";
        },
                {
            name = "What is the opposite of front?";
            questionpicture = "102q.png";
        }
    ),
        (
                {
            name = "Name a common pet?";
            questionpicture = "201q.png";
        },
                {
            name = "Name a common bird?";
            questionpicture = "202q.png";
        }
    ),
        (
                {
            name = "List 3 rooms in your house?";
            questionpicture = "301q.png";
        }
    )
)

为了处理上述谓词，数组必须如下所示

(
        {
        name = "What is the opposite of up?";
        questionpicture = "101q.png";
    },
        {
        name = "What is the opposite of front?";
        questionpicture = "102q.png";
    },
        {
        name = "Name a common pet?";
        questionpicture = "201q.png";
    },
        {
        name = "Name a common bird?";
        questionpicture = "202q.png";
    },
        {
        name = "List 3 rooms in your house?";
        questionpicture = "301q.png";
    }
)

 NSArray *questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"name CONTAINS 'the'"];


NSMutableArray *resultarray= [[NSMutableArray alloc]init];
for(int i=0;i<[questionData count];i++){
    NSArray* searchResults=[[questionData objectAtIndex:i]  filteredArrayUsingPredicate:resultPredicate];
    if([searchResults count]>0)
        [resultarray addObject:searchResults];
}
NSLog(@"%@",resultarray);
O/P:-
 (
        (
                {
            name = "What is the opposite of up?";
            questionpicture = "101q.png";
        },
                {
            name = "What is the opposite of front?";
            questionpicture = "102q.png";
        }
    )
)

编辑：-像这样尝试

(
        {
        name = "What is the opposite of up?";
        questionpicture = "101q.png";
    },
        {
        name = "What is the opposite of front?";
        questionpicture = "102q.png";
    },
        {
        name = "Name a common pet?";
        questionpicture = "201q.png";
    },
        {
        name = "Name a common bird?";
        questionpicture = "202q.png";
    },
        {
        name = "List 3 rooms in your house?";
        questionpicture = "301q.png";
    }
)

 NSArray *questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"name CONTAINS 'the'"];


NSMutableArray *resultarray= [[NSMutableArray alloc]init];
for(int i=0;i<[questionData count];i++){
    NSArray* searchResults=[[questionData objectAtIndex:i]  filteredArrayUsingPredicate:resultPredicate];
    if([searchResults count]>0)
        [resultarray addObject:searchResults];
}
NSLog(@"%@",resultarray);
O/P:-
 (
        (
                {
            name = "What is the opposite of up?";
            questionpicture = "101q.png";
        },
                {
            name = "What is the opposite of front?";
            questionpicture = "102q.png";
        }
    )
)

NSArray*questionData=[[NSArray alloc]initWithObjects:level1、level2、level3、nil]；
NSPredicate*resultPredicate=[NSPredicate predicateWithFormat:@“名称包含‘the’”）；
NSMutableArray*resultarray=[[NSMutableArray alloc]init]；
对于（int i=0；i0）
[resultarray addObject:searchResults]；
}
NSLog（@“%@”，结果数组）；
O/P:-
(
(
{
name=“up的反面是什么？”；
questionpicture=“101q.png”；
},
{
name=“前面的反面是什么？”；
questionpicture=“102q.png”；
}
)
)

我使用子查询来解决这个问题

 NSArray *questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

 NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"SUBQUERY(name, $content, $content CONTAINS %@).@count > 0", @"the"];

 NSArray *searchResults=[questionData  filteredArrayUsingPredicate:resultPredicate];

 NSLog(@"%@",searchResults);

结果：

(
    (
            {
        name = "What is the opposite of up?";
        questionpicture = "101q.png";
    },
            {
        name = "What is the opposite of front?";
        questionpicture = "102q.png";
    }
)

---

)

我使用子查询来解决这个问题

 NSArray *questionData=[[NSArray alloc] initWithObjects:level1,level2,level3, nil];

 NSPredicate *resultPredicate=[NSPredicate predicateWithFormat:@"SUBQUERY(name, $content, $content CONTAINS %@).@count > 0", @"the"];

 NSArray *searchResults=[questionData  filteredArrayUsingPredicate:resultPredicate];

 NSLog(@"%@",searchResults);

结果：

(
    (
            {
        name = "What is the opposite of up?";
        questionpicture = "101q.png";
    },
            {
        name = "What is the opposite of front?";
        questionpicture = "102q.png";
    }
)

---

)

太好了。谢谢。这个问题可以用子查询来解决，不需要使用for循环或更改数组结构。太好了。谢谢。这个问题可以通过子查询解决，不需要使用for循环或更改数组结构。