以编程方式在iPhone中混合2个Wav文件
我在将2.wav文件混合在一起时面临一个问题 我正在使用此站点中的代码: 现在我面临的问题是,代码通常适用于小于10秒的wav文件,超过10秒会导致应用程序崩溃 出于某种奇怪的原因,即使我在For循环结束时正确地释放对象,For循环包含超过10万次迭代,并且随着记录大小的增加而增加,但对象似乎不会被释放并占用内存 下面是我的for循环:以编程方式在iPhone中混合2个Wav文件,iphone,xcode,Iphone,Xcode,我在将2.wav文件混合在一起时面临一个问题 我正在使用此站点中的代码: 现在我面临的问题是,代码通常适用于小于10秒的wav文件,超过10秒会导致应用程序崩溃 出于某种奇怪的原因,即使我在For循环结束时正确地释放对象,For循环包含超过10万次迭代,并且随着记录大小的增加而增加,但对象似乎不会被释放并占用内存 下面是我的for循环: short iValueWav1Sample; short iValueWav2Sample; short iValueWavSampleAverage; f
short iValueWav1Sample;
short iValueWav2Sample;
short iValueWavSampleAverage;
for (int i=0; i<(outputWavDataSize/2); i++)
{
//simulate little endian by flipping the bytes
wav1DataBuffer1 = [[NSData alloc]initWithData:[wav1Data subdataWithRange:NSMakeRange(44 + (i*2), 1)]];
wav2DataBuffer1 = [[NSData alloc]initWithData:[wav2Data subdataWithRange:NSMakeRange(44 + (i*2), 1)]];
wav1DataBuffer2 = [[NSData alloc]initWithData:[wav1Data subdataWithRange:NSMakeRange(44 + (i*2) + 1, 1)]];
wav2DataBuffer2 = [[NSData alloc]initWithData:[wav2Data subdataWithRange:NSMakeRange(44 + (i*2) + 1, 1)]];
littleEndianHexWav1Sample = [[NSMutableData alloc] initWithData:wav1DataBuffer1];
[littleEndianHexWav1Sample appendData:[NSMutableData dataWithData:wav1DataBuffer2]];
littleEndianHexWav2Sample = [[NSMutableData alloc]initWithData:wav2DataBuffer1];
[littleEndianHexWav2Sample appendData:wav2DataBuffer2];
NSString* wav1HexString = [[littleEndianHexWav1Sample description] substringWithRange:NSMakeRange(1, 4)];
NSString* wav2HexString = [[littleEndianHexWav2Sample description] substringWithRange:NSMakeRange(1, 4)];
unsigned wav1Hexint;
unsigned wav2Hexint;
[[NSScanner scannerWithString:wav1HexString] scanHexInt:&wav1Hexint];
[[NSScanner scannerWithString:wav2HexString] scanHexInt:&wav2Hexint];
unsigned wavAverage;
wavAverage = (wav1Hexint+wav2Hexint);
iValueWav1Sample = wav1Hexint;
iValueWav2Sample = wav2Hexint;
iValueWavSampleAverage = wavAverage;
bigEndian = [[NSData alloc ]initWithBytes:&iValueWavSampleAverage length:2];
littleEndian = [[NSMutableData alloc] initWithData:[bigEndian subdataWithRange:NSMakeRange(1, 1)]];
[littleEndian appendData:[bigEndian subdataWithRange:NSMakeRange(0, 1)]];
[headerBuffer appendData:littleEndian];
//Release stuff
[wav1HexString release];
[wav2HexString release];
[wav1DataBuffer1 release];
[wav2DataBuffer1 release];
[wav1DataBuffer2 release];
[wav2DataBuffer2 release];
[littleEndianHexWav1Sample release];
[littleEndianHexWav2Sample release];
[bigEndian release];
[littleEndian release];
wav1DataBuffer1 = nil;
wav2DataBuffer1= nil;
wav1DataBuffer2 = nil;
wav2DataBuffer2 = nil;
littleEndianHexWav1Sample= nil;
littleEndianHexWav2Sample= nil;
bigEndian= nil;
littleEndian= nil;
}
现在我要做的是,在for循环中创建wav1Data和wav2Data,然后在最后释放它们
我已经解决了内存泄漏问题,但现在又出现了另一个问题,for循环的执行速度大大降低。这一定是因为每次迭代时我都会初始化文件的内容
有什么建议或想法吗 我在这里看到的是,您的应用程序可能会崩溃,这主要是因为您正在UI线程上执行更大的操作。您需要在非UI/后台线程中调用此操作。以下是您如何做到这一点:
NSOperationQueue *queue = [NSOperationQueue new];
NSInvocationOperation *operation = [[NSInvocationOperation alloc] initWithTarget:self
selector:@selector(processWave:)
object:nil;
[queue addOperation:operation];
[operation release];
[queue release];
或
更不用说您可能需要自己创建processWave
如果它仍然崩溃,请告诉我 嘿,乌斯曼,谢谢你的帮助。请检查我所做的编辑,我添加了更多信息。
NSOperationQueue *queue = [NSOperationQueue new];
NSInvocationOperation *operation = [[NSInvocationOperation alloc] initWithTarget:self
selector:@selector(processWave:)
object:nil;
[queue addOperation:operation];
[operation release];
[queue release];
[NSThread detachNewThreadSelector: @selector(processWave) toTarget:self withObject:NULL];