Sql 单列数据中的差异

我试图找出单列数据中的差异，即

Column C
date 2 (1/2/12) would check the difference from date 1 (1/1/12)
date 3 (1/3/12) would check the difference from date 2 (1/2/12)
date 4 (1/4/12) would check the difference from date 3 (1/3/12)

我想我可以创建另外两列Date days减-1和amount，然后显示差值

Column A<date>  Column B<Amount> Column C <Difference>
1/1/12            550             -150
1/2/12            400              300
1/3/12            700             -200
1/4/12            500

A列B列C列
1/1/12            550             -150
1/2/12            400              300
1/3/12            700             -200
1/4/12            500

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感谢您的帮助

您可以使用

LEAD

分析功能

SELECT  "Column A", 
        "Column B",
        (LEAD("Column B", 1) OVER (ORDER BY "Column A") - "Column B") AS "Difference"
FROM    TableName

其他

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这里是另一个使用

CTE

和

RowNum

的选项：

WITH CTE AS (
  SELECT  ColA,
        ColB,
        rownum rn
  FROM    YourTable
  ORDER BY ColA
)
SELECT C.*,
  C.ColB - C2.ColB ColC
FROM CTE C
  LEFT JOIN CTE C2 ON C.rn = C2.rn + 1

还有

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祝你好运。
@sgedes有时这些功能会被忽略。