Java 阿克曼'；函数Try-Catch问题

我目前正在做一个Ackerman函数问题，我们必须为用户输入编写一个故障保护代码。因此，如果用户的输入通常会导致程序崩溃，那么它只会发送一条消息。我能够找出整数值是否太大的例外情况，但我无法找出如何检查用户输入是否为整数。我曾尝试使用“InputMissatchException”捕捉块，但代码开始混乱并出现错误，或者根本不起作用

public static void main(String[] args) {

//creates a scanner variable to hold the users answer
Scanner answer = new Scanner(System.in);


//asks the user for m value and assigns it to variable m
System.out.println("What number is m?");
int m = answer.nextInt();




//asks the user for n value and assigns it to variable n
System.out.println("What number is n?");
int n = answer.nextInt();


try{
//creates an object of the acker method
AckerFunction ackerObject = new AckerFunction();
//calls the method
System.out.println(ackerObject.acker(m, n));
}catch(StackOverflowError e){
    System.out.println("An error occured, try again!");
}



}

}你必须把

int n = answer.nextInt();

在try块中。 然后您可能会捕获java.util.InputMismatchException

这对我很有用：

public static void main(String[] args) {

    //creates a scanner variable to hold the users answer
    Scanner answer = new Scanner(System.in);

    int m;
    int n;
    try{
        //asks the user for m value and assigns it to variable m
        System.out.println("What number is m?");
        m = answer.nextInt();
        //asks the user for n value and assigns it to variable n
        System.out.println("What number is n?");
        n = answer.nextInt();
    }catch(InputMismatchException e){
        System.out.println("An error occured, try again!");
    }
}