Java Spring mvc，maven给出noHandlerFound错误_Java_Spring_Maven

Java Spring mvc，maven给出noHandlerFound错误

java spring maven

Java Spring mvc，maven给出noHandlerFound错误,java,spring,maven,Java,Spring,Maven,我使用spring工具套件版本3.6.4.0创建了一个spring mvc maven应用程序，如下所述这是pom.xml文件 <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.o

我使用spring工具套件版本3.6.4.0创建了一个spring mvc maven应用程序，如下所述

这是pom.xml文件

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>com.mytcg</groupId>
  <artifactId>firstapp</artifactId>
  <packaging>war</packaging>
  <version>0.0.1-SNAPSHOT</version>
  <name>firstapp Maven Webapp</name>
  <url>http://maven.apache.org</url>
  <dependencies>
    <dependency>
      <groupId>junit</groupId>
      <artifactId>junit</artifactId>
      <version>3.8.1</version>
      <scope>test</scope>
    </dependency>
    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-webmvc</artifactId>
        <version>3.2.0.RELEASE</version>
    </dependency>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>servlet-api</artifactId>
        <version>2.5</version>
        <scope>provided</scope>
    </dependency>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>jstl</artifactId>
        <version>1.2</version>
        <scope>provided</scope>
    </dependency>
  </dependencies>
  <build>
    <finalName>firstapp</finalName>
  </build>
</project>

这是hello.jsp

<?xml version="1.0" encoding="ISO-8859-1" ?>
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
<title>Insert title here</title>
</head>
<body>
<h1>${greeting}</h1>
</body>
</html>

它给出了404的以下错误

Apr 04, 2016 9:40:17 AM org.springframework.web.servlet.DispatcherServlet noHandlerFound
WARNING: No mapping found for HTTP request with URI [/firstapp/greeting.html] in DispatcherServlet with name 'firstappservlet'

更改

web.xml

如下所示

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" 
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
 <load-on-startup>2</load-on-startup>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
 </web-app>

你的问题出在你的控制器上

在您的控制器中，@RequestMapping监听/greeting，但您从borwser发出一个http请求用于

您应通过以下方式更改控制器的设置：

@Controller
public class HelloController {

    @RequestMapping(value ="/greeting.html" )
    public String sayHell (Model model){

      ...
    }

}

<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
 <load-on-startup>1</load-on-startup>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>

但是，我个人的建议是，您不应该将自己与特定的实现捆绑在一起，您应该使用for@RequestMapping方法，就像您以这种方式配置dispatcherServlet一样：

@Controller
public class HelloController {

    @RequestMapping(value ="/greeting.html" )
    public String sayHell (Model model){

      ...
    }

}

<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
 <load-on-startup>1</load-on-startup>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>


调度员
org.springframework.web.servlet.DispatcherServlet
1.
调度员
/

并为您的url使用如下模式：

我希望这可以帮助您

请分享您的例外更改的完整堆栈跟踪

*.html

到

只是尝试一下什么是firstapp？它是web项目的上下文根吗？还有，什么是greeting.html？firstapp是我的应用程序名，greeting是我在控制器中调用的url尝试以下操作：我尝试添加但仍然是相同的错误尝试清理构建项目并再次运行。如果出现相同的异常，请告诉我这不会有帮助，添加旧的和不推荐的

DefaultAnnotationHandlerMapping

也不会有任何作用（

已经注册了较新的和建议

RequestMappingHandlerMapping

）。尽管看起来

/greeting

实际上不起作用，默认情况下，`a映射为

/greeting.

，它将与

greeting.html

匹配。如果您为

org.springframework.web

启用调试日志记录，您将看到检测到的映射。好的，但是如果我在注释中更改映射，我的注释可能有点短，这还取决于您是否使用

（或

@EnableWebMvc

）或者使用DispatcherServlet中的默认值以及您使用的Spring版本

    <?xml version="1.0" encoding="UTF-8"?>
    <beans xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns:context="http://www.springframework.org/schema/context"
        xmlns:mvc="http://www.springframework.org/schema/mvc"
        xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd
            http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
            http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd">
        <mvc:annotation-driven/>
        <context:component-scan base-package="com.mytcg.controller"/>


        <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name= "prefix" value="/WEB-INF/jsp/"/>
        <property name= "suffix" value=".jsp"/>
        </bean>
   <!--configuring HandlerMapping --> 
     <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/>
    </beans>

@Controller
public class HelloController {

    @RequestMapping(value ="/greeting.html" )
    public String sayHell (Model model){

      ...
    }

}

<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
</servlet>
 <load-on-startup>1</load-on-startup>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>