Java 爪哇-石头剪刀-如果错误，循环一个额外的时间，并计算获胜的次数

我不得不做一个石头纸剪刀游戏，循环5次，如果你输入了一个无效的数字，会增加循环次数。如果错误的话，我无法让它循环足够多，每当我输入错误的变量时，它确实会循环更多的次数，但次数太多了，我只需要5次正确的次数。它也不会计算玩家和电脑的分数。无论每个对手有多少次答对，它只显示玩家赢：1和电脑赢：1。请帮忙！这是我的密码

import java.util.*;
public class bmahipat_C5Lab1 {

    public static void main(String[] args) {
        Scanner reader = new Scanner (System.in);
        int player = 0, computer = 0;
        int computerScore = 0, playerScore = 0;
        int loops = 0;

        int rock = 1;
        int paper = 2;
        int scissors = 3;

        for(int i=1; i<6;i++) {
            computer = (int) (Math.random() * 3) + 1;
            System.out.println("Enter 1 for Rock, 2 for Paper, 3 for Scissors");
            player = reader.nextInt();

            if (player > scissors) {
                System.out.println("Not a valid response");
                System.out.println("Enter 1 for Rock, 2 for Paper, 3 for Scissors");
                player = reader.nextInt();
                i = -1;
            }

            if (player == computer) {
                System.out.println("Tie");
            } else if (player == rock ) {
                if(computer == paper){
                    System.out.println ("Player picked Rock, Computer picked Paper, Computer wins");
                    computerScore = +1;
                } else if(computer == scissors) {
                    System.out.println ("Player picked Rock, Computer picked Scissors, Player wins");
                    playerScore = +1;
                }    
            } else if (player == paper) {
                if(computer == rock){
                    System.out.println ("Player picked Paper, Computer picked Rock , Player wins");
                    playerScore = +1;
                } else if(computer == scissors) {
                    System.out.println ("Player picked Paper, Computer picked Scissors, Computer wins");
                    computerScore = +1;
                }   
            } else if (player == scissors) {
                if(computer == rock) {
                    System.out.println ("Player picked Scissors, Computer picked Rock , Computer wins");
                    computerScore = +1;
                } else if(computer == paper) {
                    System.out.println ("Player picked Scissors, Computer picked Paper, Player wins");
                    playerScore = +1;
                }
            }
        }

        System.out.println("");
        System.out.println("Computer Wins " + computerScore);
        System.out.println("Player Wins " + playerScore);
    }
}

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两者之间有很大的区别

computerScore =+ 1; // This is computerScore = (+1) So it will be always 1

及

同样的逻辑也适用于

  i = -1;

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代码=+1与=1相同，很可能您的意思是+=1而不是看固定次数的游戏，也许您应该一直看，直到玩了固定次数的游戏？欢迎使用，请阅读

  i = -1;