Java 在将数据插入sqlite后继续获取错误

一旦我打开应用程序，它就会提示我，不幸的是，数据库已经停止

public class Databasetest extends Activity {

private CommentDataSource datasource;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_databasetest);


    datasource = new CommentDataSource(this);
    datasource.open();
    }
}

下面是我得到的错误，有人能告诉我这是什么意思吗

(1) near "studentinfo_db": syntax error

这是我的数据源：

 public class CommentDataSource {


  private SQLiteDatabase db;
  private MySQLiteHelper dbHlp;
  private String[] allColumns = { StudentInfo.COL_ROW_ID,
      StudentInfo.COL_STUDENT_NAME };

  public CommentDataSource(Context context) {
dbHlp = new MySQLiteHelper(context);
  }

  public void open() throws SQLException {
db= dbHlp.getWritableDatabase();
  }

  public void close() {
dbHlp.close();
  }
}

这是我的MySQLiteHelper：

public class MySQLiteHelper extends SQLiteOpenHelper {


private static final String DATABASE_NAME = "studentsresult.db";
private static final int DATABASE_VERSION = 1;


public MySQLiteHelper(Context context) {
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
  }

  @Override
  public void onCreate(SQLiteDatabase database) {
    database.execSQL(StudentInfo.SQL_TABLE_NAME);
  }

  @Override
  public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    Log.w(MySQLiteHelper.class.getName(),
        "Upgrading database from version " + oldVersion + " to "
            + newVersion + ", which will destroy all old data");
    db.execSQL("DROP TABLE IF EXISTS " + StudentInfo.SQL_TABLE_NAME);
    onCreate(db);
  }
}

---

上面我已经上传了我的源代码。

你应该像这样在create中创建一个表

@Override
public void onCreate(SQLiteDatabase database) {
    database.execSQL("CREATE TABLE "+StudentInfo.SQL_TABLE_NAME);
}

修改onCreate（SQLiteDatabase）{}，如下所示

@Override
public void onCreate(SQLiteDatabase database) {

database.execSQL("CREATE TABLE "+ StudentInfo.SQL_TABLE_NAME + "(" + 
                        StudentInfo.COL_ROW_ID + " INT PRIMARY KEY," +
                        StudentInfo.COL_STUDENT_NAME+ " TEXT)" );

}

---

你能分享这个类的代码吗？

CommentDataSource

需要更多的代码来理解你的问题。发布你的查询，这是一个在线抛出的错误（studentinfo_db）我认为查询语句中有错误