Time 添加<;整数>;秒到a<;时间戳>;在PostgreSQL中

Time 添加<;整数>;秒到a<;时间戳>;在PostgreSQL中,time,casting,timedelta,Time,Casting,Timedelta,我有一个包含以下列的项目表: 开始时间列(无时区的时间戳) expiration\u time\u seconds列(integer) 例如,某些值是: SELECT start_time, expiration_time_seconds FROM whatever ORDER BY start_time; start_time | expiration_time_seconds --------------------------

我有一个包含以下列的项目表:

  • 开始时间
    列(
    无时区的时间戳
  • expiration\u time\u seconds
    列(
    integer
例如,某些值是:

SELECT start_time, expiration_time_seconds 
   FROM whatever 
       ORDER BY start_time;

         start_time         | expiration_time_seconds
----------------------------+-------------------------
 2014-08-05 08:23:32.428452 |                  172800
 2014-08-10 09:49:51.082456 |                    3600
 2014-08-13 13:03:56.980073 |                    3600
 2014-08-21 06:31:38.596451 |                    3600
 ...
如何将过期时间(以秒为单位)添加到开始时间

我尝试为
interval
命令格式化时间间隔字符串,但失败:

blah=> SELECT interval concat(to_char(3600, '9999'), ' seconds');
ERROR:  syntax error at or near "("
LINE 1: SELECT interval concat(to_char(3600, '9999'), ' seconds');
方法是创建一个固定的间隔,并将其与列中的秒数相乘:

SELECT start_time, 
       expiration_time_seconds, 
       start_time + expiration_time_seconds * interval '1 second'
FROM whatever 
ORDER BY start_time;

        start_time          | expiration_time_seconds |          end_time
----------------------------|-------------------------|----------------------------
 2014-08-05 08:23:32.428452 |                  172800 | 2014-08-07 08:23:32.428452
 2014-08-10 09:49:51.082456 |                    3600 | 2014-08-10 10:49:51.082456
 2014-08-13 13:03:56.980073 |                    3600 | 2014-08-13 14:03:56.980073
 2014-08-21 06:31:38.596451 |                    3600 | 2014-08-21 07:31:38.596451

非常感谢你!您是否可以在
开始时间+到期时间\u秒
中添加空间,使其易于可视化?