Java 数学加法代码，尝试在正确答案后结束

我的问题是，在得到正确答案后，它仍然会问问题。我错过了什么？我现在还是JAVA新手，不想因为一个简单的错误或疏忽而气馁

package acourtney;

import java.util.Scanner;

public class Hmwk03 {

public static void main(String[] args) {
    int number1 = (int)(Math.random() * 10);
    int number2 = (int)(Math.random() * 10);
    int counter = 0;

    Scanner input =new Scanner(System.in);

    System.out.print ("What is " + number1 + " + " + number2 + " ? " + "(You have three chances) ");

    int answer = input.nextInt();

        if (number1 + number2 == answer)
            System.out.println("Answer is correct");

        else
            System.out.println("Your answer is incorrect. You have two chances left ");
            counter = 2; 

    System.out.print("What is " + number1 + " + " + number2 + " ? ");

    answer = input.nextInt();

        if (number1 + number2 == answer)

            System.out.println("Answer is correct");

        else
            System.out.println("Your answer is incorrect. You have one chance left");
        counter = 3;

        System.out.print("What is " + number1 + " + " + number2 + " ? ");

        answer = input.nextInt();

        if (number1 + number2 == answer)
            System.out.println("Answer is correct");

        else
            System.out.println("Your answer is incorrect, You have failed");

        }


}

---

每次回答正确后退出程序

if (number1 + number2 == answer){
            System.out.println("Answer is correct");
System.exit(0);
}

---

每次回答正确后退出程序

if (number1 + number2 == answer){
            System.out.println("Answer is correct");
System.exit(0);
}

---

您可以使用

return

语句提前结束方法

if (number1 + number2 == answer) {
    System.out.println("Answer is correct");
    return;
}

---

您可以使用

return

语句提前结束方法

if (number1 + number2 == answer) {
    System.out.println("Answer is correct");
    return;
}

---

你的问题是你在执行

if（number1+number2==答案）
System.out.println（“答案正确”）

然后跳过

else
System.out.println（“您的答案不正确，您还有两次机会”）

然后在
计数器=2处重新拾取右键

如果您编写的If/else子句包含多行代码（例如，在输入不正确的语句后所发生的一切），则必须在整个语句周围加上大括号
{}
。最好的做法是使用大括号，即使子句只有一行。
您的问题是您正在执行

if（number1+number2==答案）
System.out.println（“答案正确”）

然后跳过

else
System.out.println（“您的答案不正确，您还有两次机会”）

然后在
计数器=2处重新拾取右键

如果您编写的If/else子句包含多行代码（例如，在输入不正确的语句后所发生的一切），则必须在整个语句周围加上大括号
{}
。最佳实践是，即使子句只有一行，也要使用大括号。
因此Java将逐行运行，这里您看到的是，一旦用户应答，程序将退出if语句，并继续执行下一个if语句

正如

 int answer = input.nextInt();

    if (number1 + number2 == answer)
        System.out.println("Answer is correct");

    else
        System.out.println("Your answer is incorrect. You have two chances left ");
        counter = 2; 

System.out.print("What is " + number1 + " + " + number2 + " ? ");

为了解决这个问题（以及您似乎有复制和粘贴代码的问题，这从来都不是一个好的做法），我建议按照

//int numOfTries is how many chances you want to give the user
for(int i = 0; i < numOfTries; i++){
    // Prompt the user for Input
    int answer = input.nextInt();

    // Check if the answer is correct
    if (number1 + number2 == answer){
        System.out.println("Answer is correct");
        //Now exit the for loop, we are done!
        return;
    }
    // What happens if the answer is not correct
    else{
        // Print out how many tries they have left as well
        System.out.println("Your answer is incorrect. You have" + i + "chance left");
    }
}

//int numotries是您希望给用户多少机会
for（int i=0；i

希望这有帮助

p.S.而不是<代码>中断
您也可以使用
return或
系统退出（0）
因此Java将逐行运行，这里您看到的是，一旦用户应答，程序就会退出if语句，并继续向下一个if语句前进

正如

 int answer = input.nextInt();

    if (number1 + number2 == answer)
        System.out.println("Answer is correct");

    else
        System.out.println("Your answer is incorrect. You have two chances left ");
        counter = 2; 

System.out.print("What is " + number1 + " + " + number2 + " ? ");

为了解决这个问题（以及您似乎有复制和粘贴代码的问题，这从来都不是一个好的做法），我建议按照

//int numOfTries is how many chances you want to give the user
for(int i = 0; i < numOfTries; i++){
    // Prompt the user for Input
    int answer = input.nextInt();

    // Check if the answer is correct
    if (number1 + number2 == answer){
        System.out.println("Answer is correct");
        //Now exit the for loop, we are done!
        return;
    }
    // What happens if the answer is not correct
    else{
        // Print out how many tries they have left as well
        System.out.println("Your answer is incorrect. You have" + i + "chance left");
    }
}

//int numotries是您希望给用户多少机会
for（int i=0；i

希望这有帮助

p.S.而不是<代码>中断
您也可以使用
return或
系统退出（0）
作为一名Java初学者，我建议您对程序进行伪代码编写，为自己提供一个蓝图。它可以帮助您将代码分解为更小的步骤

public class Hmwk03 {

public static void main(String[] args) {
    int number1 = (int)(Math.random() * 10);
    int number2 = (int)(Math.random() * 10);
    int counter = 2; // Define the number of chances they have, start at 2 since the first counter value is 0
    boolean answerCheck = false; // Define if they answer was right

    Scanner input =new Scanner(System.in);

    // Generate a for loop with a counter starting at 0
    // The loop will run either if they have more chances left
    // OR when they have gotten the answer right
    for(int i = 0; i < counter || answerCheck == true; i++) {

        System.out.print ("What is " + number1 + " + " + number2 + " ? " + "(You have three chances) "); // Output the question

        int answer = input.nextInt(); // Receive the answer

        if (number1 + number2 == answer) { // if they got the right ansser
            // Make the answerCheck true or use break here                
            answerCheck = true; 
            System.out.println("Answer is correct"); // Output the user got the correct answer
            //break; This will also work to end the loop
        } else { // they got the wrong answer
            System.out.println("Your answer is incorrect. You have " + counter - i + " chances left."); // Note they got the answer wrong and tell them how many chances they have left 
        }
    }
    if(!answerCheck) System.out.print(" You have failed"); // If they failed to get the answer correct, print out final statement.

}

公共类Hmwk03{
公共静态void main（字符串[]args）{
int number1=（int）（Math.random（）*10）；
int number2=（int）（Math.random（）*10）；
int counter=2；//定义它们的机会数，从2开始，因为第一个计数器值是0
boolean answerCheck=false；//定义他们的答案是否正确
扫描仪输入=新扫描仪（System.in）；
//生成计数器从0开始的for循环
//如果他们还有更多的机会，循环将运行
//或者当他们得到正确的答案时
for（int i=0；i
作为Java的初学者，我建议您对程序进行伪编码，为自己绘制蓝图。它可以帮助您将代码分解为更小的步骤

public class Hmwk03 {

public static void main(String[] args) {
    int number1 = (int)(Math.random() * 10);
    int number2 = (int)(Math.random() * 10);
    int counter = 2; // Define the number of chances they have, start at 2 since the first counter value is 0
    boolean answerCheck = false; // Define if they answer was right

    Scanner input =new Scanner(System.in);

    // Generate a for loop with a counter starting at 0
    // The loop will run either if they have more chances left
    // OR when they have gotten the answer right
    for(int i = 0; i < counter || answerCheck == true; i++) {

        System.out.print ("What is " + number1 + " + " + number2 + " ? " + "(You have three chances) "); // Output the question

        int answer = input.nextInt(); // Receive the answer

        if (number1 + number2 == answer) { // if they got the right ansser
            // Make the answerCheck true or use break here                
            answerCheck = true; 
            System.out.println("Answer is correct"); // Output the user got the correct answer
            //break; This will also work to end the loop
        } else { // they got the wrong answer
            System.out.println("Your answer is incorrect. You have " + counter - i + " chances left."); // Note they got the answer wrong and tell them how many chances they have left 
        }
    }
    if(!answerCheck) System.out.print(" You have failed"); // If they failed to get the answer correct, print out final statement.

}

公共类Hmwk03{
公共静态void main（字符串[]args）{
int number1=（int）（Math.random（）*10）；