Java：在2D数组中搜索字符串并显示数据
我正在创建一个程序，作为给定单词的翻译。我已经用我正在使用的数据创建了一个文本文件，将其读入第0列的二维数组中，第1列翻译，总共16行。我会提示用户输入一个字符串，并将该字符串、2D和空白字符串传递给我的翻译方法turnKlingon。我使用字符串标记器来挑选特定的单词。我的问题是，我不知道如何在第0列中搜索我的2D数组以查找英语，而只打印第1列的翻译单词Java：在2D数组中搜索字符串并显示数据,java,arrays,string,2d,Java,Arrays,String,2d,我正在创建一个程序，作为给定单词的翻译。我已经用我正在使用的数据创建了一个文本文件，将其读入第0列的二维数组中，第1列翻译，总共16行。我会提示用户输入一个字符串，并将该字符串、2D和空白字符串传递给我的翻译方法turnKlingon。我使用字符串标记器来挑选特定的单词。我的问题是，我不知道如何在第0列中搜索我的2D数组以查找英语，而只打印第1列的翻译单词 import java.util.*; import java.io.*; public class project9 { publ
import java.util.*;
import java.io.*;
public class project9
{
public static void main(String[] args)
throws java.io.IOException
{
System.out.println("Klingon Translator");
System.out.println();
System.out.println();
String userString = " ";
userString = loadUserString();
String[][] translate = new String[16][2];
loadTranslateString(translate);
String Klingon = " ";
turnKlingon(Klingon, userString, translate);
}
public static String loadUserString()
{
Scanner input = new Scanner(System.in);
String s1 = " ";
System.out.println("Please enter a sentence that you would like translated to Klingon: ");
s1 = input.nextLine().trim().toUpperCase();
return s1;
}
public static void loadTranslateString(String[][] translate)
throws java.io.IOException
{
String filName = " ";
filName = "C:\\tmp\\transKling.txt";
Scanner input = new Scanner(new File(filName));
for (int row = 0; row < translate.length; row++)
{
for (int col = 0; col < translate[row].length; col++)
translate[row][col] = input.nextLine();
}
input.close();
}
public static void turnKlingon(String Klingon, String userString, String[][] translate)
{
String userStringPassed = userString;
String[][] translatePassed = translate;
String s2 = " ";
StringTokenizer st = new StringTokenizer(userStringPassed);
int numberOfWords = st.countTokens();
System.out.println("Number of Tokens: "+ numberOfWords);
int counter = 1;
while (counter <= numberOfWords)
{
s2 = st.nextToken(); //string tokenizer
System.out.print(s2 + "_"); //string tokenizer
for(int r = 0; r < translate.length; r++)
{
for(int c = 0; c < translate[r].length; c++)
{
if (translate[r][c].compareTo(s2) == 0)
{
translate[0] = translate[1];
}
}
System.out.println(translate[0] + "," + translate[1]);
counter++; //string tokenizer
}//end while
}
}
}
在花了几个小时处理这些代码之后，我终于解决了自己的问题。我还在main方法中添加了一个while-true循环，允许用户多次翻译，还可以选择翻译成另一种语言德语，尽管我在回答中省略了该方法
import java.util.*;
import java.io.*;
public class project9
{
public static void main(String[] args)
throws java.io.IOException
{
Scanner input = new Scanner(System.in);
System.out.println("English to Klingon/German Translator");
System.out.println();
System.out.println();
while (true)
{
int again = 999;
int language = 999;
String userString = " ";
userString = loadUserString();
String[][] translate = new String[16][2];
loadTranslateString(translate);
System.out.println("Would you like to translate to Klingon or German? \n Press 1 for Klingon: \n Press 2 for German: ");
language = input.nextInt();
if (language == 1)
{
turnKlingon(userString, translate);
}
else if (language == 2)
{
turnGerman(userString, translate);
}
else
{
System.out.println("Invalid input");
}
System.out.println();
System.out.println();
System.out.println("Would you like to translate another sentence? \n Press 1 for yes or 0 for no: ");
again = input.nextInt();
if (again == 0)
{
System.out.println("Goodbye!");
break;
}
else if (again == 1)
{
continue;
}
}
}
public static String loadUserString()
{
Scanner input = new Scanner(System.in);
String s1 = " ";
System.out.println("Please enter a sentence that you would like translated: ");
s1 = input.nextLine().trim().toUpperCase();
return s1;
}
public static void loadTranslateString(String[][] translate)
throws java.io.IOException
{
String filName = " ";
filName = "C:\\tmp\\transKling.txt";
Scanner input = new Scanner(new File(filName));
for (int row = 0; row < translate.length; row++)
{
for (int col = 0; col < translate[row].length; col++)
translate[row][col] = input.nextLine();
}
input.close();
}
public static void turnKlingon(String userString, String[][] translate)
{
String userStringPassed = userString;
String[][] translatePassed = translate;
String s2 = " ";
StringTokenizer st = new StringTokenizer(userStringPassed);
int numberOfWords = st.countTokens();
System.out.println();
System.out.println("Any words that cannot be directly \n translated will remain in English");
System.out.println("____________________________________");
System.out.println();
System.out.print("Translation: ");
int counter = 1;
boolean found = false;
int translateCounter = 0;
while (counter <= numberOfWords)
{
s2 = st.nextToken(); //string tokenizer
//string tokenizer
for(int r = 0; r < 16; r++)
{
for(int c = 0; c < 18; c++)
{
found = false;
if (translateCounter == 16)
{
System.out.print(s2+ " ");
translateCounter = 0;
break;
}
else if (translate[r][0].compareTo(s2) == 0)
{
found = true;
}
else if (translate[r][0].compareTo(s2) != 0)
{
found = false;
r++;
c = -1;;
translateCounter++;
continue;
}
if (found == true)
{
System.out.print(translate[r][1]+ " ");
translateCounter = 0;
c = -1;
r = -1;
break;
}
}
counter++;//string tokenizer
break;
}//end while
}
}
可能需要研究使用hashmap。然后您可以使用英文单词作为值。Maxqueue的注释为+1：Java不是Excel。您将如何向后翻译Maxqueue？还有文档：和基本教程：