Java 使用Android异步Http处理成功请求返回

我是android新手，来自iOS，我对Java及其所有功能不太了解。我正在尝试构建一个用户需要在启动时登录的应用程序。我使用的是一个私有API，使用方式如下：

https://apiUrl.com/login?login=login&password=password

它返回给我一个JSon对象：

{
token: "qqdpo9i7qo3m8lldksin6cq714"
}

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

因此，我在代码中所做的很简单：

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

MainActivity.java：

Button button = (Button) findViewById(R.id.loginButton);

        button.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                String login = (String) ((EditText) findViewById (R.id.userName)).getText().toString();
                String password = (String) ((EditText) findViewById (R.id.password)).getText().toString();

                if (login != "" && password != "")
                {
                    HashMap<String, String> postElements = new HashMap<String, String>();
                    postElements.put("login", login);
                    try {
                        postElements.put("password", URLEncoder.encode(password, "utf-8"));
                    } catch (UnsupportedEncodingException e) {
                        e.printStackTrace();
                    }
                    Button button = (Button) findViewById(R.id.loginButton);
                    button.setText("Login in ...");

                    String queryLogin = "https://apiUrl.com/login?";

                    String urlString = "";
                    try {
                        urlString = "login=";
                        urlString += URLEncoder.encode(login, "UTF-8");
                        urlString += "&password=";
                        urlString += URLEncoder.encode(password, "UTF-8");
                    } catch (UnsupportedEncodingException e) {

                        // if this fails for some reason, let the user know why
                        e.printStackTrace();
                        Toast.makeText(getApplicationContext(), "Error: " + e.getMessage(), Toast.LENGTH_LONG).show();
                    }

                    apiQuery.loginQuery(queryLogin, urlString);
}

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

我的实现工作正常，我有一条ToastMessage，它显示在屏幕上，带有“Login Success”（当然，当它失败时是“Login Error”）

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

但我不知道如何处理这种成功，以便传递给我创建的其他活动

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

我想这样做：

if (apiQuery.loginQuery(...)) 
   show(activityLogged); // Where activityLogged is another activity

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

更新

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

我添加了以下几行：

if (jsonObject.has("token")) 
{
    /*Toast.makeText(_mainContext, "Login Success!",     Toast.LENGTH_LONG).show();*/
    token = jsonObject.optString("token");
    // 8. For now, just log results
    Log.d("APIQuery Success", jsonObject.toString());
    Intent i = new Intent(_mainContext, MainActivityLogged.class);
    _mainContext.startActivity(i);
}

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

我的清单文件如下所示：

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

---

您只需编写一个意图，即可移动到onSuccess回调中的下一个活动

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

 @Override
              public void onSuccess(JSONObject jsonObject) {
                    String token = "";

                    if (jsonObject.has("token")) {
                    /*Toast.makeText(_mainContext, "Login Success!", Toast.LENGTH_LONG).show();*/
                    token = jsonObject.optString("token");
                    Intent i = new Intent(context,LoggedActivity.class);
                    context.startActivity(i);
                     }
              }

在上述代码中

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

  Intent i = new Intent(context,LoggedActivity.class);
                    startActivity(i);

---

这用于导航到下一页。还要确保您在清单文件中声明了活动。

您还可以通过以下意图将一些数据传递给下一个活动：

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

@Override
public void onSuccess(JSONObject jsonObject) {
    String token = "";
    if (jsonObject.has("token")) {
        /*Toast.makeText(_mainContext, "Login Success!", Toast.LENGTH_LONG).show();*/
        token = jsonObject.optString("token");
        Intent i = new Intent(context,LoggedActivity.class);
        i.putExtra("token", token);
        startActivity(i);
    }
}

然后从下一个活动（在onCreate（）中）检索令牌，如下所示：

            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <!-- ATTENTION: This data URL was auto-generated. We recommend that you use the HTTP scheme.
              TODO: Change the host or pathPrefix as necessary. -->
            <data
                android:host="epidroid.charvoz.example.com"
                android:pathPrefix="/mainactivitylogged"
                android:scheme="http" />
        </intent-filters>

---

你应该读到：我必须修改一点，它没有编译，

Intent I=newintent（_mainContext，MainActivityLogged.class）_主上下文。起始触觉（i）。但是，当我点击Log按钮时，应用程序退出。您是否已将意向过滤器添加到新活动中？没有必要这样放，或者你能给我整个清单文件吗，好的，我添加了
I.addFlags（Intent.FLAG\u ACTIVITY\u NEW\u TASK）现在可以工作了！感谢您的帮助：）我已经使用异步http编写了一个示例，如果需要，您可以查看该示例