如何在java中使用单个循环打印两个长度不同但数据类型相同的数组?
我试过这个如何在java中使用单个循环打印两个长度不同但数据类型相同的数组?,java,arrays,loops,Java,Arrays,Loops,我试过这个 public static void main(String[] args) throws ArrayIndexOutOfBoundsException { int arr1[]= {1,2,3,4,5}; int arr2[]= {6,7}; for(int i=0;i<arr1.length;i++) { System.out.println(arr1[i]); System.out.println(arr2[i]); } } public
public static void main(String[] args) throws ArrayIndexOutOfBoundsException
{
int arr1[]= {1,2,3,4,5};
int arr2[]= {6,7};
for(int i=0;i<arr1.length;i++)
{
System.out.println(arr1[i]);
System.out.println(arr2[i]);
}
}
publicstaticvoidmain(字符串[]args)抛出ArrayIndexOutOfBoundsException
{
int arr1[]={1,2,3,4,5};
int arr2[]={6,7};
对于(inti=0;i,您必须找到最大长度,然后关心您可以输出什么以不触及边界
public static void main(String[] args) throws ArrayIndexOutOfBoundsException
{
int arr1[]= {1,2,3,4,5};
int arr2[]= {6,7};
int max = arr1.length;
if (max < arr2.length){
max = arr2.length;
}
for(int i=0;i<max;i++)
{
if (i < arr1.length){
System.out.println(arr1[i]);
}
if (i < arr2.length){
System.out.println(arr2[i]);
}
}
}
publicstaticvoidmain(字符串[]args)抛出ArrayIndexOutOfBoundsException
{
int arr1[]={1,2,3,4,5};
int arr2[]={6,7};
int max=arr1.1长度;
如果(最大值 对于(int i=0;i循环到两个数组的最大长度,并仅打印索引有效的数组元素
public static void main(String[] args) throws ArrayIndexOutOfBoundsException
{
int arr1[]= {1,2,3,4,5};
int arr2[]= {6,7};
for(int i=0;i<Math.max(arr1.length, arr2.length);i++)
{
if(i<arr1.length)
System.out.println(arr1[i]);
if(i<arr2.length)
System.out.println(arr2[i]);
}
}
publicstaticvoidmain(字符串[]args)抛出ArrayIndexOutOfBoundsException
{
int arr1[]={1,2,3,4,5};
int arr2[]={6,7};
对于(inti=0;i试试这个,我想这会有用的
int arr1[]= {1,2,3,4,5};
int arr2[]= {6,7};
int a1 = arr1.length();
int a2 = arr2.length();
int n = a1 > a2 ? a1 : a2;
for(int i = 0; i < n; i++) {
if(a1 > i)
System.out.println(arr1[i]);
if(a2 > i)
System.out.println(arr2[i]);
}
intarr1[]={1,2,3,4,5};
int arr2[]={6,7};
int a1=arr1.length();
int a2=arr2.length();
int n=a1>a2?a1:a2;
对于(int i=0;ii)
系统输出println(arr1[i]);
如果(a2>i)
System.out.println(arr2[i]);
}
祝您好运或者,要一个接一个地打印它们:
int arr1[]= {1,2,3,4,5};
int arr2[]= {6,7};
for (int i=0; i < arr1.length + arr2.length; ++i)
{
if (i < arr1.length)
System.out.println (arr1 [i]);
else
System.out.println (arr2 [i - arr1.length]);
}
intarr1[]={1,2,3,4,5};
int arr2[]={6,7};
对于(int i=0;i
您可以使用下面的代码。您仍然可以满足两个数组长度相同的条件。只有当数组长度不同时,这才有效
public static void main(String[] args) throws ArrayIndexOutOfBoundsException
{
int arr1[]= {1,2,3,4,5};
int arr2[]= {6,7};
int arr1Length = arr1.length;
int arr2Length = arr2.length;
if(arr1.length>arr2.length)
{
for(int i=0;i<arr1.length;i++)
{
System.out.println(arr1[i]);
if(i<arr2.length)
{
System.out.println(arr2[i]);
}
else continue;
}
else{
for(int i=0;i<arr2.length;i++)
{
if(i<arr1.length)
{
System.out.println(arr1[i]);
}
else continue;
System.out.println(arr2[i]);
}
}
}
publicstaticvoidmain(字符串[]args)抛出ArrayIndexOutOfBoundsException
{
int arr1[]={1,2,3,4,5};
int arr2[]={6,7};
int arr1Length=arr1.length;
int arr2Length=arr2.length;
如果(arr1.长度>arr2.长度)
{
对于(int i=0;如果您共享它引发的错误,iIt将很有帮助。查看您的代码,因为arr1
比arr2
长,循环将继续经过arr2
的长度,在该长度处没有元素,从而导致失败。如果我们知道预期输出是什么,这也会很有帮助。如果我能够d、 …可能的副本