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Java 从PagerAdapter到Fragment_Java_Android_Android Intent_Android Fragments - Fatal编程技术网

Java 从PagerAdapter到Fragment

Java 从PagerAdapter到Fragment,java,android,android-intent,android-fragments,Java,Android,Android Intent,Android Fragments,我需要从theageadapter.java内部SliderHome.java获取传递的值。我如何实现这一点?我试了很多,但没有成功 这是我的代码: ageadapter.java public class ThePagerAdapter extends PagerAdapter { Context context; @Override public int getCount() { return list.size(); } @Override public boolean isV

我需要从
theageadapter.java
内部
SliderHome.java
获取传递的值。我如何实现这一点?我试了很多,但没有成功

这是我的代码:

ageadapter.java

public class ThePagerAdapter extends PagerAdapter {
Context context;

@Override
public int getCount() {
    return list.size();
}

@Override
public boolean isViewFromObject(View view, Object object) {
    return view == ((RelativeLayout) object);
}

public ThePagerAdapter(Context context,List<Slider> list) {
    this.list = list;
    this.context = context;
}

@Override
public Object instantiateItem(final ViewGroup container, int position) {
    // Declare Variables
    ImageView imgflag;

    inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View itemView = inflater.inflate(R.layout.image_item, container, false);

    // Capture position and set to the TextViews
    final String id =  list.get(position).getId();

    imgflag = (ImageView) itemView.findViewById(R.id.imageView);

    imgflag.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {
            // TODO Auto-generated method stub

            Intent i = new Intent(context, SliderMore.class);
            i.putExtra("slider_id", id);
            context.startActivity(i);
        }
    });

    ((ViewPager) container).addView(itemView);

    return itemView;
}

@Override
public void destroyItem(ViewGroup container, int position, Object object) {
    // Remove viewpager_item.xml from ViewPager
    ((ViewPager) container).removeView((RelativeLayout) object);

}
}
public class SliderHome extends Fragment {

ViewPager viewPager;
ImageView iv2,iv3;
String slider_id;

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {

    View rootView = inflater.inflate(R.layout.slider_more, container, false);

    viewPager = (ViewPager) rootView.findViewById(R.id.viewPager);
    iv2 = (ImageView) rootView.findViewById(R.id.imageView2);
    iv3 = (ImageView) rootView.findViewById(R.id.imageView3);

    return rootView;
}

有解决办法吗?提前谢谢

在这种情况下,我喜欢使用工厂方法模式

例如:

public static MatchDetailSummaryFragment newInstance(String matchIdString, int position) {
    MyFragment fragment = new MyFragment();
    Bundle args = new Bundle();
    args.putString(ARGS_MY_ID, matchIdString);
    args.putInt(ARG_POSITION,position);
    fragment.setArguments(args);
    return fragment;
}

public MyFragment() {
    // Required empty public constructor
}

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    this.mPosition = getArguments().getInt(ARG_POSITION);
    this.id = getArguments().getString(ARGS_MY_ID) != null)
}
您可以调用以下命令:

public void fillMyPagerAdapter()
{

    mChildFragments = new Hashtable<Integer,GxuBaseFragment>();
    int count = 0;

        MyFragment a = MyFragment.newInstance(Integer.toString(my.getId()),count);
        mChildFragments.put(count,a);
        count += 1;

    mViewPagerAdapter.setTabHolderScrollingContent(this);
    mPager.setAdapter(mViewPagerAdapter);
    mPagerSlidingTabStrip.setViewPager(mPager);
    mPagerSlidingTabStrip.setOnPageChangeListener(this);

}
public void fillMyPagerAdapter()
{
mChildFragments=新哈希表();
整数计数=0;
MyFragment a=MyFragment.newInstance(Integer.toString(my.getId()),count);
mChildFragments.put(计数,a);
计数+=1;
mViewPagerAdapter.setTabHolderScrollingContent(此);
mPager.setAdapter(mViewPagerAdapter);
MPagerSlidingTastrip.setViewPager(mPager);
MPagerSlidingTastrip.setOnPageChangeListener(此);
}

这段代码可能不起作用,因为它是我的产品代码的几个摘录,但它将解释主要思想。

作为一个例子,阅读谷歌自己的第一个片段示例:@Blackbelt:yes,我想获得
I.putExtra(“slider\u id”,id)
SliderMore
@AnkurAggarwal中的值:如何使其成为可能?不可能使用startActivity(intent)启动一个片段,请阅读谷歌指南片段,将参数传递给片段,您可能会使用fragment.setArguments(bundle)