用于循环生成MAC地址的Java
正在尝试使用以下内容循环MAC地址值:用于循环生成MAC地址的Java,java,for-loop,mac-address,Java,For Loop,Mac Address,正在尝试使用以下内容循环MAC地址值: String macAddr = "AA:BB:CC:DD:"; char[] chars = {'A', 'B', 'C', 'D', 'E', 'F'}; String[] strings = {"0", "0", "0", "0"}; for (int i=0; i<strings.length; i++) { //counter from 0 to F for (int d = 0; d <= 9; d++)
String macAddr = "AA:BB:CC:DD:";
char[] chars = {'A', 'B', 'C', 'D', 'E', 'F'};
String[] strings = {"0", "0", "0", "0"};
for (int i=0; i<strings.length; i++)
{
//counter from 0 to F
for (int d = 0; d <= 9; d++)
{
strings[i] = ""+d;
print();
}
for (int d = 0; d< chars.length; d++)
{
strings[i] = ""+chars[d];
print();
}
}
但我被碾过了:
AA:BB:CC:DD:00:0DAA:BB:CC:DD:00:0E
AA:BB:CC:DD:00:0F
AA:BB:CC:DD:00:0F
AA:BB:CC:DD:00:1F
AA:BB:CC:DD:00:2F
AA:BB:CC:DD:00:3F 这两个问题是每个交叉点的双重值(例如AA:BB:CC:DD:00:0F) 并且每个值都在F处停止 我试图将其作为: AA:BB:CC:DD:00:0D
AA:BB:CC:DD:00:0E
AA:BB:CC:DD:00:0F
AA:BB:CC:DD:00:11
AA:BB:CC:DD:00:12
AA:BB:CC:DD:00:13 等等
干杯:)使用
long
存储您的mac地址,并创建一个小函数将其转换为字符串
public static String toMacString(long mac) {
if (mac > 0xFFFFFFFFFFFFL || mac < 0)
throw new IllegalArgumentException("mac out of range");
StringBuffer m = new StringBuffer(Long.toString(mac, 16));
while (m.length() < 12) m.insert(0, "0");
for (int j = m.length() - 2; j >= 2; j-=2)
m.insert(j, ":");
return m.toString().toUpperCase();
}
public static void main(String[] args) {
long mac = 0xAABBCCDD0000L;
for (long i = 0; i < 1000; i++)
System.out.println(toMacString(mac++));
}
为了保持简单,请尝试以下方法:
public static void main(String... args) {
String macAddr = "AA:BB:CC:DD:";
for (int i = 0; i < 256; i++) {
for (int j = 0; j < 256; j++) {
String fullAddr = String.format(macAddr + "%02X:%02X", i, j);
System.out.println(fullAddr);
}
}
}
String[]Mac={“0”、“1”、“2”、“3”、“4”、“5”、“6”、“7”、“8”、“9”、“A”、“B”、“C”、“D”、“E”、“F”};
随机rd=新随机();
nextInt路(15);
字符串结果=”;
对于(int i=0;我为什么不只是数到16并转换成十六进制?我不知道怎么做,这就是为什么下面的答案得到了我的“答案”。简单的解决方案正好是我想要做的。添加一个toUpperCase()
,结果应该是完美的。(+1)托马斯:观点不错,修正了@莫里斯·佩里:在你的评论发布之前已经修复了…)@MauricePerry:无论如何,更新了一个超出范围的检查。这是一个很好的方法,但对于初学者来说很复杂,@Bohemian的回答更像是对我所做的修改。@spuriosity heh,okey。。不过,我建议您将mac表示为“mac
”类中包装的long
或byte[]
。
AA:BB:CC:DD:00:00
AA:BB:CC:DD:00:01
AA:BB:CC:DD:00:02
AA:BB:CC:DD:00:03
AA:BB:CC:DD:00:04
AA:BB:CC:DD:00:05
AA:BB:CC:DD:00:06
....
AA:BB:CC:DD:03:DF
AA:BB:CC:DD:03:E0
AA:BB:CC:DD:03:E1
AA:BB:CC:DD:03:E2
AA:BB:CC:DD:03:E3
AA:BB:CC:DD:03:E4
AA:BB:CC:DD:03:E5
AA:BB:CC:DD:03:E6
AA:BB:CC:DD:03:E7
public static void main(String... args) {
String macAddr = "AA:BB:CC:DD:";
for (int i = 0; i < 256; i++) {
for (int j = 0; j < 256; j++) {
String fullAddr = String.format(macAddr + "%02X:%02X", i, j);
System.out.println(fullAddr);
}
}
}
AA:BB:CC:DD:00:00
AA:BB:CC:DD:00:01
AA:BB:CC:DD:00:..
AA:BB:CC:DD:00:10
AA:BB:CC:DD:00:0A
AA:BB:CC:DD:00:..
AA:BB:CC:DD:00:0F
AA:BB:CC:DD:00:10
AA:BB:CC:DD:00:..
AA:BB:CC:DD:00:FF
AA:BB:CC:DD:01:00
AA:BB:CC:DD:..:..
AA:BB:CC:DD:FF:FF
String[] Mac = {"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"};
Random rd = new Random();
rd.nextInt(15);
String result="";
for(int i=0;i<6;i++){
String a = Mac[rd.nextInt(15)];
String b = Mac[rd.nextInt(15)];
result+=a+b;
if(i<5){
result+=":";
}
}