Java 排序算法[实现为一种方法]
我想了解一下如何使用排序算法问题方法中代码的最后一个方法,以便按顺序对每个玩家的名字进行排序。我不能将它放在Main方法中,因为它需要来自Questions方法中的循环的名称字符串Java 排序算法[实现为一种方法],java,algorithm,sorting,Java,Algorithm,Sorting,我想了解一下如何使用排序算法问题方法中代码的最后一个方法,以便按顺序对每个玩家的名字进行排序。我不能将它放在Main方法中,因为它需要来自Questions方法中的循环的名称字符串 public static void main(String[] args){ int players = Integer.parseInt(JOptionPane.showInputDialog("Please tell me how many players are taking part in
public static void main(String[] args){
int players = Integer.parseInt(JOptionPane.showInputDialog("Please tell me how many players are taking part in this quiz!"));
/* --------------------------- Questions in Arrays --------------------------- */
String[] question = {"Question 1: ",
"Question 2: ",
"Question 3: ",
"Question 4: ",
"Question 5: " };
String[] answer = {"ans1",
"ans2",
"ans3",
"ans4",
"ans5" };
questions(question, answer, players);
/* --------------------------- Questions in Arrays --------------------------- */
} /* End of Main Method */
/* Questions Method */
public static void questions(String[] question, String[] answer, int n) {
String[] name = new String[n]; // Player Names
int[] playerscore = new int[n]; // Argument for Score
String[] que = new String[question.length]; //Questions for Loops
/* --------------------------- For loop for number of players --------------------------- */
for (int i = 0; i < n; i++)
{
playerscore[i] = 0;
name[i] = JOptionPane.showInputDialog("What is your name player"+ (i+1) +"?");
JOptionPane.showMessageDialog(null,"Hello :"+ name[i] + " Player number " +(i+1)+ ". I hope your ready to start!");
/* --------------------------- Loop in Loop for questions --------------------------- */
for (int x=0; x<question.length; x++) {
que[x] = JOptionPane.showInputDialog(question[x]);
if(que[x].equals(answer[x]))
{
playerscore[i] = playerscore[i] + 1;
}
else {
JOptionPane.showMessageDialog(null,"Wrong!");
}
} // End for loop for Question
System.out.println("\nPlayer: "+(i+1)+ " Name: "+name[i]+"\tScore"+playerscore[i]+" out of 5.);
/* --------------------------- Loop in Loop for questions --------------------------- */
} // End for loop for player number
} //End method questions
}让您的提问方法返回带有玩家姓名的数组。
这样,您就可以使用返回的值调用sortNames方法。为什么不使用Arrays.sort方法对名称进行排序?您正在使用复杂的方法对字符串进行排序
public static String[] sortNames(String name[])
{
Arrays.sort(name);
return name;
}
供参考
如果你想让游戏变得简单,那么你可以为每个玩家创建一个对象,并将其保存在HashMap中
您可以使用java中的HashMap实现这一点,其中key作为播放器名称,String和Value作为一个对象,其中包含您需要的关于播放器的所有信息
Map<String, Object> map = new HashMap<String, Object>();
您还可以像这样对hashmap进行排序
HashMap<String, PlayerInfo> map = new HashMap<String, PlayerInfo>();
ValueComparator bvc = new ValueComparator(map);
TreeMap<String,PlayerInfo> sorted_map = new TreeMap<String,PlayerInfo>(bvc);
map.put(playerName1, playerInfo1);
map.put(playerName2, playerInfo2);
map.put(playerNamen, playerInfon);
sorted_map.putAll(map);
System.out.println("results: "+sorted_map);
我应该如何在提问方法中实现这一点?另外,我使用了这个复杂的方法,因为这是我们经历过的一个算法。我想使用我已经拥有的算法,因为我不想把代码搞得一团糟。有没有办法将sortName方法传递到playerscore显示上方的questions方法中,以便按顺序对名称进行排序?没有,你不能这样做,因为如果你对名称进行排序,那么另一张地图中的球员的相应分数将指向旧名称顺序。因此,对于两个不同的数组,不能单独对一个数组进行排序。当我尝试从question方法返回name数组时,它表示该值已经声明。
Map<String, Object> map = new HashMap<String, Object>();
HashMap<String, PlayerInfo> map = new HashMap<String, PlayerInfo>();
ValueComparator bvc = new ValueComparator(map);
TreeMap<String,PlayerInfo> sorted_map = new TreeMap<String,PlayerInfo>(bvc);
map.put(playerName1, playerInfo1);
map.put(playerName2, playerInfo2);
map.put(playerNamen, playerInfon);
sorted_map.putAll(map);
System.out.println("results: "+sorted_map);