Java 字符出现

可能重复：

我试图制作一个程序来检查一个字符在字符串中出现的次数。 我设法将其转换为ASCII，但我也希望能够计算某个字符或ASCII值在字符串中出现的时间

   String myString = "Hello.";
    for (int i=0;i<myString.length();i++){
char c = myString.charAt(i);
int j = (int) c;
System.out.println("ASCII OF "+c +" = " + j + ".");
    }

如果您除了转换为ASCII之外还有其他选择，请告诉我。

这个怎么样：

String myString = "Hello.";
char searchChar = 'l';
int count = 0;

for (int i = 0; i < myString.length(); i++) {
    char c = myString.charAt(i);
    if (c == searchChar) {
        count++;
    }
}

System.out.println(count);

这可以很容易地转化为一种可多次使用的方法：

/**
 * Return the number of occurences of a character in the specified String.
 * 
 * @param string the string to search
 * @param searchChar the char to search for
 * @return the number of occurences of searchChar in string
 */
public int countChars(String string, char searchChar) {
    int count = 0;
    for (int i = 0; i < string.length(); i++) {
        char c = string.charAt(i);
        if (c == searchChar) {
            count++;
        }
    }
    return count;
}

这个怎么样：

String myString = "Hello.";
char searchChar = 'l';
int count = 0;

for (int i = 0; i < myString.length(); i++) {
    char c = myString.charAt(i);
    if (c == searchChar) {
        count++;
    }
}

System.out.println(count);

这可以很容易地转化为一种可多次使用的方法：

/**
 * Return the number of occurences of a character in the specified String.
 * 
 * @param string the string to search
 * @param searchChar the char to search for
 * @return the number of occurences of searchChar in string
 */
public int countChars(String string, char searchChar) {
    int count = 0;
    for (int i = 0; i < string.length(); i++) {
        char c = string.charAt(i);
        if (c == searchChar) {
            count++;
        }
    }
    return count;
}